如何通过按钮事件实现窗体的移动？

Question

   通过按钮事件实现窗体在水平方向、垂直方向、对角方向的移动

Answer 1

按纽事件里添加 窗体.Location.x ++,或者 窗体.Location.y++;

Answer 2

上this.Top--;
下this.Top--;
左 this.Left--;
右 this.Left++;

Answer 3

this.Location = new Point(this.Location.X + 1, this.Location.Y); //从左到右
this.Location = new Point(this.Location.X - 1, this.Location.Y); //从右到左this.Location = new Point(this.Location.X, this.Location.Y + 1); //从上到下
this.Location = new Point(this.Location.X, this.Location.Y - 1); //从下到上this.Location = new Point(this.Location.X + 1, this.Location.Y + 1); //从左上到右下
this.Location = new Point(this.Location.X + 1, this.Location.Y + 1); //从右下到左上
// 其他方向，照此发挥this.Location.X+this.Width == 屏幕宽度　这时　this.Location.X　＝０　//其他类似处理

Answer 4

加定时器，在Tick事件中执行移动操作，用按扭控制　Timer.Start() Timer.Stop

Answer 5

 public partial class Form1 : Form
    {
        public Form1()
        {
            InitializeComponent();
        }        private Timer t = new Timer();
        private Timer t1 = new Timer();        private void Form1_Load(object sender, EventArgs e)
        {
            t.Interval = 10;
            t.Tick += new EventHandler(button4_Click);//到达时间的时候执行事件； 
            t1.Interval = 10;
            t1.Tick += new EventHandler(button5_Click);//到达时间的时候执行事件； 
           
           
        }       //左移
        private void button4_Click(object sender, EventArgs e)
        {
            Rectangle rect = new Rectangle();
            rect = Screen.GetWorkingArea(this);
            t1.Stop();
            t.Start();
              
                this.Left--;
                if (this.Left < 0)
                {
                    this.Left = rect.Width;
                }
         
        }
       //右移
        private void button5_Click(object sender, EventArgs e)
        {
             Rectangle rect = new Rectangle();
            rect = Screen.GetWorkingArea(this);
            t.Stop();
            t1.Start();            this.Left++;
            if (this.Left >= rect.Width)
            {
                this.Left = 0;
            }
    }

Answer 6

这个问题简单啊，你用个timer的ticker来控制他，同时判断他到了什么位置应该做什么动作，不如到了边界又反弹会来呀，还是怎么的，而你的按钮空间是需要控制timer的enable属性就行了。

Answer 7

嗯。建议使用Timer来实现，如果使用代码直接实现，估计CPU占用比较大

Answer 8

System.Windows.Forms.Screen.PrimaryScreen.Bounds.Width   
System.Windows.Forms.Screen.PrimaryScreen.Bounds.Height

Answer 9

 this.Location.X=0; 这句反不回去啊

Answer 10

屏幕
System.Windows.Forms.Screen.PrimaryScreen.Bounds.Width   
System.Windows.Forms.Screen.PrimaryScreen.Bounds.Height
 
工作区 
C# codeScreen.PrimaryScreen.WorkingArea.Height;
Screen.PrimaryScreen.WorkingArea.Width;
this.Location.X=0;
改成
this.Location = new Point(0, this.Location.Y); //从左到右

Answer 11

this.Location = new Point(this.Location.X + 5, this.Location.Y);
            if (this.Location.X + this.Width == Screen.PrimaryScreen.Bounds.Width)
                this.Location = new Point(0, this.Location.Y); 大哥  这样还是不行啊  移出窗体后还是无法从屏幕的左边出来

Answer 12

改为:this.Location = new Point(this.Location.X + 5, this.Location.Y);
if (this.Location.X > Screen.PrimaryScreen.Bounds.Width)
this.Location = new Point(0, this.Location.Y);