js如何获取treeview选中节点的值

Question

js如何获取treeview选中节点的值, 在通过按钮确认吧选中的值传在另外一个页面请问谁有JS获取treeview选中节点好方法，急用，  谢谢     

Answer 1

我曾经试着JS遍历过treeview  遍历出来的就没有那个层次结构了 

Answer 2

点击treeview 的treenode后  肯定要触发后台代码的建议你用下iframe好了  

Answer 3

<asp:TreeView ID="TreeView1" runat="server" onclick="javascript:client_OnTreeNodeChecked();" NodeIndent="10" ShowCheckBoxes="All" ShowLines="True"> 
function checkParent (obj) 
        { 
            while(obj != null) 
            { 
                var tagName = obj.tagName.toLowerCase(); 
                if(tagName == "div" && obj.id == "TreeView1") 
                { 
                    return; 
                } 
                
                if(tagName == "table") 
                { 
                    var checkBox = obj.getElementsByTagName("INPUT"); 
                    if(checkBox.length >0) 
                    { 
                        checkBox[0].checked = true; 
                    } 
                    obj = obj.parentElement.previousSibling; 
                } 
                else 
                    obj = obj.parentElement; 
            } 
        } 
                    
        function client_OnTreeNodeChecked() 
        { 
            var obj = window.event.srcElement; 
            var treeNodeFound = false; 
            var checkedState; 
            if (obj.tagName == "INPUT" && obj.type == "checkbox") 
            { 
                var treeNode = obj; 
                checkedState = treeNode.checked; 
                
                if(checkedState) 
                { 
                    checkParent(obj); 
                } 
                
                do 
                { 
                    obj = obj.parentElement; 
                } 
                while (obj.tagName != "TABLE") 
                
                var parentTreeLevel = obj.rows[0].cells.length; 
                var parentTreeNode = obj.rows[0].cells[0]; 
                
                var tables = obj.parentElement.getElementsByTagName("TABLE"); 
                var numTables = tables.length 
                if (numTables >= 1) 
                { 
                    for (i=0; i < numTables; i++) 
                    { 
                      if(tables[i] == obj) 
                      { 
                            treeNodeFound = true; 
                            i++; 
                            if(i == numTables) 
                            { 
                                return; 
                            } 
                        } 
                        if (treeNodeFound == true) 
                        { 
                            var childTreeLevel = tables[i].rows[0].cells.length; 
                            if (childTreeLevel > parentTreeLevel) 
                            { 
                                var cell = tables[i].rows[0].cells[childTreeLevel - 1]; 
                                var inputs = cell.getElementsByTagName("INPUT"); 
                                inputs[0].checked = checkedState; 
                            } 
                            else 
                            { 
                                return; 
                            } 
                        } 
                    } 
                } 
            } 
        } 
http://topic.csdn.net/u/20100524/17/6f38c355-6f99-49b5-8e62-2bcb2dc72385.html