字符串分析

Question

分析指定字符在字符串中出现的次数（如A1,A3）在下列字符串中出现的次数A1,A1,A1,A1,A1,A1,A1,A1,A1,A3,A3,A3,A3,A3,A3,A3,A3,A3,A3,A3,A3,A3,A3

Answer 1

 string temp = "A1,A1,A1,A1,A1,A1,A1,A1,A1,A3,A3,A3,A3,A3,A3,A3,A3,A3,A3,A3,A3,A3,A3";
                string[] temp_list = temp.Split(',');
                int count1 = temp_list.Where(a => a.Equals("A1")).Count();//9
                int count2 = temp_list.Where(a => a.Equals("A3")).Count();//14

Answer 2

本帖最后由 bdmh 于 2012-08-01 16:52:35 编辑

  

Answer 3

用个HashTable(Of String,Integer)，添加这些字符串,查到已有就Value+1，没有就添一个Key

Answer 4

var query="A1,A1,A1,A1,A1,A1,A1,A1,A1,A3,A3,A3,A3,A3,A3,A3,A3,A3,A3,A3,A3,A3,A3".Split(',')
.GroupBy(x=>x).Select(g=>new{g.Key,c=g.Count()});

Answer 5

string s = "A1,A1,A1,A1,A1,A1,A1,A1,A1,A3,A3,A3,A3,A3,A3,A3,A3,A3,A3,A3,A3,A3,A3";
var query = from x in s.Split(',')
            group x by x into g
            select g + "出现了" + g.Count().ToString() + "次";
foreach (string item in query)
{
    Console.WriteLine(item);
}

Answer 6

这么多人用Linq啊，唉，我书还没有看到那儿呢。

Answer 7

string sr = "A1,A1,A1,A1,A1,A1,A1,A1,A1,A3,A3,A3,A3,A3,A3,A3,A3,A3,A3,A3,A3,A3,A3";
        string[] st = sr.Split(',');
        Dictionary<string, int> dic = new Dictionary<string, int>();
        foreach (string s in st)
        {
            if (dic.ContainsKey(s))
                dic[s]++;
            else
                dic.Add(s, 0);
        }