hibernate配置文件错误 BasUserInfo is not mapped [from BasUserInfo]

Question

hibernate的cfg文件如下：
<session-factory>
<property name="dialect">
org.hibernate.dialect.SQLServerDialect
</property>
<property name="hibernate.connection.url">
                    jdbc:sqlserver://172.16.4.252:1433;databasename=CemsCenter
<!--jdbc:MySQL://172.16.4.187:3306/overtime-->
</property>
<property name="hibernate.connection.username">sa</property>
<property name="hibernate.connection.password">123</property>
<!-- <property name="connection.driver_class">
org.gjt.mm.mysql.Driver
</property>-->
                
                <property name="hibernate.connection.driver_class">
                    com.microsoft.sqlserver.jdbc.SQLServerDriver
 <!--com.mysql.jdbc.Driver-->
</property>
                <!-- C3P0连接池设定-->    
  
<!--            <property name="hibernate.connection.provider_class">org.hibernate.connection.C3P0ConnectionProvider
            </property>    
            <property name="hibernate.c3p0.max_size">20</property>    
            <property name="hibernate.c3p0.min_size">5</property>    
            <property name="hibernate.c3p0.timeout">120</property>    
            <property name="hibernate.c3p0.max_statements">100</property>    
            <property name="hibernate.c3p0.idle_test_period">120</property>    
            <property name="hibernate.c3p0.acquire_increment">2</property>    -->
                   
<property name="myeclipse.connection.profile">
sqlServer
</property>
                
<property name="show_sql">true</property>
                 <mapping resource="testDao/BasUserInfo.hbm.xml" />
             
</session-factory>hibernate的hbm文件如下：
<hibernate-mapping>
    <class name="testDao.BasUserInfo" table="Bas_UserInfo" schema="dbo" >
        <id name="id" type="java.lang.String">
            <column name="ID" length="36" />
            <generator class="native" />
        </id>
        <property name="account" type="java.lang.String">
            <column name="Account" />
        </property>
        <property name="userName" type="java.lang.String">
            <column name="UserName"  />
        </property>
        <property name="pwd" type="java.lang.String">
            <column name="PWD"  />
        </property>
        <property name="roleId" type="java.lang.String">
            <column name="RoleID"  />
        </property>
        <property name="email" type="java.lang.String">
            <column name="EMail"  />
        </property>
        <property name="del" type="java.lang.Short">
            <column name="Del" />
        </property>
    </class>
</hibernate-mapping>java类如下：
public class BasUserInfo implements java.io.Serializable
{    // Fields    private String id;
    private String account;
    private String userName;
    private String pwd;
    private String roleId;
    private String email;
    private Short  del;    // Constructors    /** default constructor */
    public BasUserInfo()
    {
    }    /** minimal constructor */
    public BasUserInfo(String id, String account, String pwd)
    {
        this.id = id;
        this.account = account;
        this.pwd = pwd;
    }    /** full constructor */
    public BasUserInfo(String id, String account, String userName, String pwd, String roleId, String email, Short del)
    {
        this.id = id;
        this.account = account;
        this.userName = userName;
        this.pwd = pwd;
        this.roleId = roleId;
        this.email = email;
        this.del = del;
    }    // Property accessors    public String getId()
    {
        return this.id;
    }    public void setId(String id)
    {
        this.id = id;
    }    public String getAccount()
    {
        return this.account;
    }    public void setAccount(String account)
    {
        this.account = account;
    }    public String getUserName()
    {
        return this.userName;
    }    public void setUserName(String userName)
    {
        this.userName = userName;
    }    public String getPwd()
    {
        return this.pwd;
    }    public void setPwd(String pwd)
    {
        this.pwd = pwd;
    }    public String getRoleId()
    {
        return this.roleId;
    }    public void setRoleId(String roleId)
    {
        this.roleId = roleId;
    }    public String getEmail()
    {
        return this.email;
    }    public void setEmail(String email)
    {
        this.email = email;
    }    public Short getDel()
    {
        return this.del;
    }    public void setDel(Short del)
    {
        this.del = del;
    }
}
错误代码如下：
Exception in thread "main" org.hibernate.hql.ast.QuerySyntaxException: BasUserInfo is not mapped [from BasUserInfo]
at org.hibernate.hql.ast.util.SessionFactoryHelper.requireClassPersister(SessionFactoryHelper.java:158)
at org.hibernate.hql.ast.tree.FromElementFactory.addFromElement(FromElementFactory.java:87)
at org.hibernate.hql.ast.tree.FromClause.addFromElement(FromClause.java:70)
at org.hibernate.hql.ast.HqlSqlWalker.createFromElement(HqlSqlWalker.java:255)
at org.hibernate.hql.antlr.HqlSqlBaseWalker.fromElement(HqlSqlBaseWalker.java:3056)
at org.hibernate.hql.antlr.HqlSqlBaseWalker.fromElementList(HqlSqlBaseWalker.java:2945)
at org.hibernate.hql.antlr.HqlSqlBaseWalker.fromClause(HqlSqlBaseWalker.java:688)
at org.hibernate.hql.antlr.HqlSqlBaseWalker.query(HqlSqlBaseWalker.java:544)
at org.hibernate.hql.antlr.HqlSqlBaseWalker.selectStatement(HqlSqlBaseWalker.java:281)
at org.hibernate.hql.antlr.HqlSqlBaseWalker.statement(HqlSqlBaseWalker.java:229)
at org.hibernate.hql.ast.QueryTranslatorImpl.analyze(QueryTranslatorImpl.java:228)
at org.hibernate.hql.ast.QueryTranslatorImpl.doCompile(QueryTranslatorImpl.java:160)
at org.hibernate.hql.ast.QueryTranslatorImpl.compile(QueryTranslatorImpl.java:111)
at org.hibernate.engine.query.HQLQueryPlan.<init>(HQLQueryPlan.java:77)
at org.hibernate.engine.query.HQLQueryPlan.<init>(HQLQueryPlan.java:56)
at org.hibernate.engine.query.QueryPlanCache.getHQLQueryPlan(QueryPlanCache.java:72)
at org.hibernate.impl.AbstractSessionImpl.getHQLQueryPlan(AbstractSessionImpl.java:133)
at org.hibernate.impl.AbstractSessionImpl.createQuery(AbstractSessionImpl.java:112)
at org.hibernate.impl.SessionImpl.createQuery(SessionImpl.java:1623)
at com.sdl.dao.HisData.test.main(test.java:47)各位大侠们 急啊 这问题太奇怪了 我明明映射了hbm文件啊 它怎么会报这个错误呢？

Answer 1

看看TOMCAT中有没有这个实体类  

Answer 2

没看上面的代码 一看错误提示 凭我个人经验 是因为SQL写错了 from 后面的那个名字要大写 或者 此类映射错误 

Answer 3

// Fields
 
    private String id;
    private String account;
    private String userName;Id 没指定主键生成方式 没标明 id为主键  :  如@Id  @GeneratorValue(...)  ; 实体类 上面 没加上 @Entity

Answer 4

看一下 BasUserInfo.hbm.xml ， BasUserInfo.java 两个相对位置对不对。
可能你的BasUserInfo.hbm.xml放错地方了。

Answer 5

Exception in thread "main" org.hibernate.hql.ast.QuerySyntaxException: BasUserInfo is not mapped [from BasUserInfo]
这句话是关键，如果你是用的hql的话，在你的sql语句应该写Statement stmt=stmtFactory.createStatement("from BasUserInfo","where");
from后面接的是实体类名，还有BasUserInfo.hbm.xml，BasUserInfo.java这两个配置文件最好放在一起，在实体类那个包里

Answer 6

非常赞同，明显是 执行hql时候出现了问题，应该是 hql语句的问题

Answer 7

都报了BasUserInfo is not mapped竟然还说是hql有问题....再看看最初抛出的at org.hibernate.hql.ast.util.SessionFactoryHelper.requireClassPersister(SessionFactoryHelper.java:158)。  
requireClassPersister   就是缺少持久化类啊 可能是BasUserInfo.hbm.xml，BasUserInfo.java没放一起吧