REST风格的项目部署在tomcat上，静态资源如何访问

Question

服务器：tomcat6.0.29
我的项目想用spring mvc框架，URL采用REST风格，但是这样一来，服务器上的静态资源访问不到了，麻烦高手给看一下。
web.xml文件如下<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<!-- Spring前端控制器 -->
<servlet>
<servlet-name>dingcanServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet
</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>classpath:/context/servlet/dingcan-servlet.xml
</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dingcanServlet</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<!--以下是静态文件路径配置，如果不配置，则对静态文件的请求也会被dingcanServlet拦截-->
<servlet-mapping>
<servlet-name>default</servlet-name>
<url-pattern>/script/*</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>default</servlet-name>
<url-pattern>/images/*</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>default</servlet-name>
<url-pattern>/style/*</url-pattern>
</servlet-mapping>
<servlet-mapping>
<servlet-name>default</servlet-name>
<url-pattern>/html/*</url-pattern>
</servlet-mapping>

</web-app>

Answer 1

    @Override
    public void configureDefaultServletHandling(DefaultServletHandlerConfigurer config) {
        config.enable();
    }