Spring整合hibernate出错报空指针错误求解

Question

完成一个向数据库存一个人的id和name的功能
谢谢
我觉得xml文件最美信心就先放前面了
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
       xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
       xmlns:context="http://www.springframework.org/schema/context"
       xsi:schemaLocation="http://www.springframework.org/schema/beans 
           http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
           http://www.springframework.org/schema/context
           http://www.springframework.org/schema/context/spring-context-3.0.xsd">
      <bean name="p" class="com.person.model.PersonDao"/>         
                  <bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close">
  <property name="driverClassName" value="com.mysql.jdbc.Driver"/>
  <property name="url" value="jdbc:mysql://127.0.0.1:3306/Spring"/> 
  <property name="username" value="root"/>
  <property name="password" value="87660057"/>
    </bean></beans>
接口：
public interface PersonService {
  public void save(Person person); 
}
接口的实现：
public class PersonDao implements PersonService{
public DataSource getDataSource() {
return dataSource;
}
@Resource
public void setDataSource(DataSource dataSource) {
this.dataSource = dataSource;
}
private DataSource dataSource;
@Override
public void save(Person person) {
// TODO Auto-generated method stub
try {
Connection con;
con=dataSource.getConnection();
con.createStatement().executeUpdate("insert into person values(null,'zhansan')");
con.close();
} catch (SQLException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
System.out.println("rs");
}
}
管理存入数据的类：
public class PersonServiceBean implements PersonService {
//  @Resource 
//  private SessionFactory sessionFactory;
private PersonDao persondao;
public PersonDao getPersondao() {
return persondao;
}
public void setPersondao(PersonDao persondao) {
this.persondao = persondao;
}
public void save(Person person){
persondao.save(person);
  } 
}实体类代码：
package com.person.model;import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.Id;@Entity
public class Person {
private Integer id;
  private String name;
  
  public Person(){}
  
  public Person(String name) {
    this.name = name;
  }
  @Id
  @GeneratedValue
  public Integer getId() {
    return id;
  }
  public void setId(Integer id) {
    this.id = id;
  }
  public String getName() {
    return name;
  }
  public void setName(String name) {
    this.name = name;
  }
}

Answer 1

擦 抱歉 忘复制错误信息了java.lang.NullPointerException
at com.person.model.PersonDao.save(PersonDao.java:24)
at com.person.model.PersonServiceBean.save(PersonServiceBean.java:21)
at com.first.spring.Persontest.testSpring(Persontest.java:42)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25)
at java.lang.reflect.Method.invoke(Method.java:597)
at org.junit.runners.model.FrameworkMethod$1.runReflectiveCall(FrameworkMethod.java:44)
at org.junit.internal.runners.model.ReflectiveCallable.run(ReflectiveCallable.java:15)
at org.junit.runners.model.FrameworkMethod.invokeExplosively(FrameworkMethod.java:41)
at org.junit.internal.runners.statements.InvokeMethod.evaluate(InvokeMethod.java:20)
at org.junit.internal.runners.statements.RunBefores.evaluate(RunBefores.java:28)
at org.junit.internal.runners.statements.RunAfters.evaluate(RunAfters.java:31)
at org.junit.runners.BlockJUnit4ClassRunner.runChild(BlockJUnit4ClassRunner.java:73)
at org.junit.runners.BlockJUnit4ClassRunner.runChild(BlockJUnit4ClassRunner.java:46)
at org.junit.runners.ParentRunner.runChildren(ParentRunner.java:180)
at org.junit.runners.ParentRunner.access$000(ParentRunner.java:41)
at org.junit.runners.ParentRunner$1.evaluate(ParentRunner.java:173)
at org.junit.internal.runners.statements.RunBefores.evaluate(RunBefores.java:28)
at org.junit.internal.runners.statements.RunAfters.evaluate(RunAfters.java:31)
at org.junit.runners.ParentRunner.run(ParentRunner.java:220)
at org.eclipse.jdt.internal.junit4.runner.JUnit4TestReference.run(JUnit4TestReference.java:46)
at org.eclipse.jdt.internal.junit.runner.TestExecution.run(TestExecution.java:38)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:467)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:683)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.run(RemoteTestRunner.java:390)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.main(RemoteTestRunner.java:197)

Answer 2

public void save(Person person);这里面的person没有值吧，实例化了么？看你的xml里面没有配置啥啊，实体类在xml里面怎么配置给spring管理的？

Answer 3

persondao你配置了么？你的dataSource通过@Resource配置了，但是在Service中的persondao没有配置啊

Answer 4

你好，我配置了的
<bean id=xx class=xxxxx>
<property name=persondao ref=p>大概就是初始化persondao这个。

Answer 5

java.lang.NullPointerException
at com.person.model.PersonDao.save(PersonDao.java:24)
这个24行指的是哪一行哦