java webservice 做的服务端怎么接收客户端发送的报文xml

Question

下面是java用httpclient做的webservice客户端，现在想知道怎么服务端怎么接受这个soapRequestData xml数据并返回一个xmlpublic static void testHttpClientWebservice(){
  String soapRequestData = "<?xml version=\"1.0\" encoding=\"utf-8\"?>" +
     "<soap12:Envelope xmlns:xsi=\"       "<soap12:Body>" +
        " <getCountryCityByIp xmlns=\"       "    <theIpAddress>221.226.1.218</theIpAddress>" +
      "   </getCountryCityByIp>" +
     "  </soap12:Body>" +
     "</soap12:Envelope>";
PostMethod postMethod =new PostMethod(" http://www.webxml.com.cn/WebServices/IpAddressSearchWebService.asmx");
  byte[] b;
  try {
   postMethod.setRequestBody(new NameValuePair[] {
         new NameValuePair("test" , soapRequestData)
   });
   b = soapRequestData.getBytes("utf-8");
   InputStream is = new ByteArrayInputStream(b,0,b.length);
   RequestEntity re = new InputStreamRequestEntity(is,b.length,"application/soap+xml; charset=utf-8");
   postMethod.setRequestEntity(re);
   HttpClient httpClient = new HttpClient();
   int statusCode = httpClient.executeMethod(postMethod);
   System.out.println(postMethod.getResponseBodyAsString());
  } catch (IOException e) {
   e.printStackTrace();
  }
  
 }

Answer 1

1.根据客户端提供的wsdl文件生成服务端代码，可以通过wsdl2java工具生成。