Servlet下得不到参数

Question

我客户端用public static String sendRequest(String url, Map<String, String> params,
Map<String, File> files) throws Exception {
HttpURLConnection conn = (HttpURLConnection) new URL(url)
.openConnection();
String BOUNDARY = java.util.UUID.randomUUID().toString();
String PREFIX = "--", LINEND = "\r\n";
String MULTIPART_FROM_DATA = "application/octet-stream";
String CHARSET = "UTF-8"; conn.setConnectTimeout(5 * 1000);
conn.setRequestMethod("POST");
conn.setRequestProperty("Charset", "UTF-8");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setDoOutput(true);
conn.setDoInput(true);
conn.setUseCaches(false);
conn.setRequestProperty("Content-Type", MULTIPART_FROM_DATA
+ ";boundary=" + BOUNDARY); // 首先组拼文本类型的参数 StringBuilder sb = new StringBuilder();
System.out.println(url);
DataOutputStream outStream = new DataOutputStream(conn.getOutputStream()); // outStream.write(sb.toString().getBytes());
// 发送文件数据 if (files != null)
for (Map.Entry<String, File> file : files.entrySet()) {
StringBuilder sb1 = new StringBuilder();
sb1.append(PREFIX);
sb1.append(BOUNDARY);
sb1.append(LINEND);
sb1.append("Content-Disposition: form-data; name=\"file\"; filename=\""
+ file.getKey() + "\"" + LINEND);
sb1.append("Content-Type: application/octet-stream; charset="
+ CHARSET + LINEND);
sb1.append(LINEND);
outStream.write(sb1.toString().getBytes());
InputStream is = new FileInputStream(file.getValue());
byte[] buffer = new byte[1024];
int len = 0;
while ((len = is.read(buffer)) != -1) {
outStream.write(buffer, 0, len);
}
is.close();
outStream.write(LINEND.getBytes());
}
byte[] end_data = (PREFIX + BOUNDARY + PREFIX + LINEND).getBytes();
outStream.write(end_data);
outStream.flush(); int res = conn.getResponseCode();
System.out.println("response Code==="+res);
if (res == 200) {
InputStream in = conn.getInputStream();
int ch;
StringBuilder sb2 = new StringBuilder();
BufferedReader bw=new BufferedReader(new InputStreamReader(in,CHARSET));
String line="";

while((line=bw.readLine())!=null){
sb2.append(line);
}
System.out.println(sb2);
in.close();
return sb2.toString();
} outStream.close();
conn.disconnect();
return null;
}
向服务器 发数据     服务器用servlet 得不到  添加的参数 
 改用struts能直接得到添加的参数，  方法应该没问题，就是servlet下 加的参数全部得不到 ，是不是要另外解析的

Answer 1

传参数那块 
StringBuilder sb = new StringBuilder();
    for (Map.Entry<String, String> entry : params.entrySet())
    {
        sb.append(PREFIX);
        sb.append(BOUNDARY);
        sb.append(LINEND);
        sb.append("Content-Disposition: form-data; name=\"" + entry.getKey() + "\"" + LINEND);
        sb.append("Content-Type: text/plain; charset=" + CHARSET + LINEND);
        sb.append("Content-Transfer-Encoding: 8bit" + LINEND);
        sb.append(LINEND);
        sb.append(entry.getValue());
        sb.append(LINEND);
    }     DataOutputStream outStream = new DataOutputStream(conn.getOutputStream());
    outStream.write(sb.toString().getBytes());

Answer 2

InputStream inputStream=request.getInputStream();
BufferedReader buf=new BufferedReader(new InputStreamReader(inputStream,"utf-8"));
String line="";
while((line=buf.readLine())!=null)
System.out.println(line);得到的流能打印--27693a33-29ab-4045-b3a6-f3b716f28a0d
Content-Disposition: form-data; name="pageNo"
Content-Type: text/plain; charset=UTF-8
Content-Transfer-Encoding: 8bit1
--27693a33-29ab-4045-b3a6-f3b716f28a0d
Content-Disposition: form-data; name="userId"
Content-Type: text/plain; charset=UTF-8
Content-Transfer-Encoding: 8bit48
--27693a33-29ab-4045-b3a6-f3b716f28a0d
Content-Disposition: form-data; name="pageSize"
Content-Type: text/plain; charset=UTF-8
Content-Transfer-Encoding: 8bit10
--27693a33-29ab-4045-b3a6-f3b716f28a0d
Content-Disposition: form-data; name="type"
Content-Type: text/plain; charset=UTF-8
Content-Transfer-Encoding: 8bit74
--27693a33-29ab-4045-b3a6-f3b716f28a0d
Content-Disposition: form-data; name="friendId"
Content-Type: text/plain; charset=UTF-8
Content-Transfer-Encoding: 8bit101
--27693a33-29ab-4045-b3a6-f3b716f28a0d--
但直接用request.getParamter("userId") 就得不到参数

Answer 3

我也想求解 我的是url自动生成的后面加？page=* 然后servlet 都得不到 后来我在页面用个 隐藏的name属性

Answer 4

Servlet要一个HttpServletRequest request的Request对象
然后取网址传过来的参数用request.getParameter("name");