onClick = "return f1()"

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
  <head>
    <title>MyHtml.html</title>
<script language="javaScript">
function f1(){
var email = form1.email.value;
//var pattern = /^[a-zA-Z]{1}([a-zA-Z0-9]|[._]){4,19}$/;
var pattern = /^[a-zA-Z0-9][a-zA-Z0-9]{2,8}@(163|126)\.(com|cn)$/;
var flag = pattern.test(email);
if(flag){
alert("It's correct!!");
return ture;
}else{
alert("It's incorrect!!");
return flase;
}
}
</script>
  </head>

  <body>
<form action="login.do" name="form1">
<input type="text" name="email">
<input type="submit" value="确定" onClick="return f1()">
</form>
  </body>
</html>
<input type="submit" value="确定" onClick="return f1()">
这样写不管验证对错都会跳到login.do
帮看看吧

解决方案 »

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    <form action="login.do" name="form1" onsubmit="return f1()">
        <input type="text" name="email">
        <input type="submit" value="确定">
    </form>
1楼正解!
还有楼主这个地方貌似写错了
return flase;---->return false;
正解或者
<input type="button"JS里面if(true){
form1.submit();
}
<html>
  <head>
    <title>MyHtml.html</title>
    <script language="javaScript">
        function f1(){
            var email = form1.email.value;
            //var pattern = /^[a-zA-Z]{1}([a-zA-Z0-9]|[._]){4,19}$/;
            var pattern = /^[a-zA-Z0-9][a-zA-Z0-9]{2,8}@(163|126)\.(com|cn)$/;
            var flag = pattern.test(email);
            if(flag){
                alert("It's correct!!");
                return ture;
            }else{
                alert("It's incorrect!!");
                return flase;
            }
            form1.submit();
        }
    </script>
  </head>

  <body>
    <form action="login.do" name="form1">
        <input type="text" name="email">
        <input type="button" value="确定" onClick="return f1()">
    </form>
  </body>
</html>
submit直接提交了有事件多用button在func中提交
submit是什么是不管怎样都提交，把submit换成button就ok 了
这个应该用AJAX吧  不刷新吧
return flase;应该是
return false;