JPA用例出错

Question

今天在学习JPA时，做一个用例，出现下面错误，有时候在Hibernate里也会出现，请各位路过大侠看下：java.lang.NoSuchFieldError: INSTANCE
at org.hibernate.type.BasicTypeRegistry.<init>(BasicTypeRegistry.java:94)
at org.hibernate.type.TypeResolver.<init>(TypeResolver.java:59)
at org.hibernate.cfg.Configuration.<init>(Configuration.java:250)
at org.hibernate.cfg.Configuration.<init>(Configuration.java:302)
at org.hibernate.cfg.AnnotationConfiguration.<init>(AnnotationConfiguration.java:96)
at org.hibernate.ejb.Ejb3Configuration.<clinit>(Ejb3Configuration.java:133)
at org.hibernate.ejb.HibernatePersistence.createEntityManagerFactory(HibernatePersistence.java:55)
at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:51)
at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:33)
at kun.model.PersonCURDTest.testAdd(PersonCURDTest.java:16)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25)
at java.lang.reflect.Method.invoke(Method.java:597)
at org.junit.runners.model.FrameworkMethod$1.runReflectiveCall(FrameworkMethod.java:44)
at org.junit.internal.runners.model.ReflectiveCallable.run(ReflectiveCallable.java:15)
at org.junit.runners.model.FrameworkMethod.invokeExplosively(FrameworkMethod.java:41)
at org.junit.internal.runners.statements.InvokeMethod.evaluate(InvokeMethod.java:20)
at org.junit.runners.BlockJUnit4ClassRunner.runNotIgnored(BlockJUnit4ClassRunner.java:79)
at org.junit.runners.BlockJUnit4ClassRunner.runChild(BlockJUnit4ClassRunner.java:71)
at org.junit.runners.BlockJUnit4ClassRunner.runChild(BlockJUnit4ClassRunner.java:49)
at org.junit.runners.ParentRunner$3.run(ParentRunner.java:193)
at org.junit.runners.ParentRunner$1.schedule(ParentRunner.java:52)
at org.junit.runners.ParentRunner.runChildren(ParentRunner.java:191)
at org.junit.runners.ParentRunner.access$000(ParentRunner.java:42)
at org.junit.runners.ParentRunner$2.evaluate(ParentRunner.java:184)
at org.junit.runners.ParentRunner.run(ParentRunner.java:236)
at org.eclipse.jdt.internal.junit4.runner.JUnit4TestReference.run(JUnit4TestReference.java:50)
at org.eclipse.jdt.internal.junit.runner.TestExecution.run(TestExecution.java:38)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:467)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:683)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.run(RemoteTestRunner.java:390)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.main(RemoteTestRunner.java:197)

Answer 1

此处是源代码：persistence.xml:<?xml version="1.0" encoding="UTF-8"?>
<persistence xmlns="http://java.sun.com/xml/ns/persistence"
             xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
             xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd"
             version="2.0">
<!-- 持久化单元 -->
    <persistence-unit name="JPAPersistence" transaction-type="RESOURCE_LOCAL">
        <properties>
            <property name="hibernate.dialect" value="org.hibernate.dialect.Oracle10gDialect"/>
            <property name="hibernate.connection.driver_class" value="oracle.jdbc.driver.OracleDriver"/>
            <property name="hibernate.connection.url" value="jdbc:oracle:thin:@127.0.0.1:1521:orcl"/>
            <property name="hibernate.connection.username" value="junit"/>
            <property name="hibernate.connection.password" value="junit"/>            <property name="hibernate.hbm2ddl.auto" value="update"/>
            <property name="hibernate.show_sql" value="true"/>
            <property name="hibernate.format_sql" value="true"/>      
     
            
        </properties>
    </persistence-unit>
</persistence>Person.java:
package kun.model;import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.Id;@Entity
public class Person { private int id;
private String name; @Id
@GeneratedValue
// (strategy=GenerationType.AUTO)
public int getId() {
return id;
} public void setId(int id) {
this.id = id;
} public String getName() {
return name;
} public void setName(String name) {
this.name = name;
}}
JunitCase:
package kun.model;import javax.persistence.EntityManager;
import javax.persistence.EntityManagerFactory;
import javax.persistence.Persistence;import org.junit.Test;public class PersonCURDTest { @Test
public void testAdd() {

//EntityManagerFactory 类似于Hibernate SessionFactory
//"JPAPersistence" 持久化单元名称
EntityManagerFactory emf = Persistence.createEntityManagerFactory("JPAPersistence");
EntityManager em = emf.createEntityManager();

Person p = new Person();
p.setName("link");

em.getTransaction().begin(); //开启事务
em.persist(p);
em.getTransaction().commit(); //提交事务
em.close();
emf.close();
}}请各位大侠看下，小弟不胜感激！！！

Answer 2

数据库里生成Person这张表没？

Answer 3

没有，我做测试，在：
JunitCase：EntityManagerFactory emf = Persistence.createEntityManagerFactory("JPAPersistence");
这一句时，就出错了，后面都没有机会执行

Answer 4

用的数据库是Oracle 11g，而且以前在做Hibernate时，用Mysql5也出过类似问题，只是后来忘了怎么解决的了。

Answer 5

java.lang.NoSuchFieldError: INSTANCE
个人认为少点啥，如果代码没错，就是表有问题

Answer 6

我看你的表并没有写注入生成表。在@Entity下加@Table(name="person") 然后就是仔细检查，你的配置是不是对的。

Answer 7

我就是要用实体Bean生成表，那个@Table注解本来就可以不用写的，生成表名与Entity名称相同，检查过配置，没有问题。纠结啊~~~~

Answer 8

I solved my problem.
I had to delete hibernate-annotations.jar, because I had it already in hibernate3.jar...

Answer 9

刚刚又检查过配置，应该是没错，直接用JDBC也作过测试，还是不行？？？

Answer 10

多谢各位解答，我刚刚把jar包换成hibernate4.0的后，程序不再出错，下面是我使用到的jar包，是Hibernate 4.0.1 Final，之前用的是3.6.9，只是到现在还不知道问题出在哪~~~~如果各位有兴趣，可以去试下Hibernate3.6.9为什么不行？？？

Answer 11

Hibernate3.6 和 hibernate-jpa-2.0 包冲突。