从数据库中取出多条数据,每条数据中包含一个二进制图片。现在要在页面上将该多条数据展示出来,问题是只能显示一个图片,其它图片没有显示。不过,该图片的大小是所有图片大小之和。我在网上baidu找到一个解释是:代码中将servletResponse.setContentType("image/jpeg");程序将所有图片作为一个图片来处理了。。
请高手帮忙解决,代码如下:......
ResultSet rs = null;
try {
rs = stmt.executeQuery(sql);
} catch (Exception e) {
System.out.println(e.toString() + "<br>");
}try {
while (rs.next()) {
try {
servletResponse.setContentType("image/jpeg");
InputStream is = rs.getBinaryStream(1);
int size = is.available();
byte[] bytes = new byte[size];
int n = 0;
while ((n = is.read(bytes)) != -1) {
out.write(bytes, 0, n);
out.write("\r\n".getBytes());
}
} catch (Exception e) {
System.out.println("write image error: " + e.toString());
}
}
out.flush();
} catch (Exception e) {
System.out.println("unable to close statment" + e.toString());
}
out.close();
......
请高手帮忙解决,代码如下:......
ResultSet rs = null;
try {
rs = stmt.executeQuery(sql);
} catch (Exception e) {
System.out.println(e.toString() + "<br>");
}try {
while (rs.next()) {
try {
servletResponse.setContentType("image/jpeg");
InputStream is = rs.getBinaryStream(1);
int size = is.available();
byte[] bytes = new byte[size];
int n = 0;
while ((n = is.read(bytes)) != -1) {
out.write(bytes, 0, n);
out.write("\r\n".getBytes());
}
} catch (Exception e) {
System.out.println("write image error: " + e.toString());
}
}
out.flush();
} catch (Exception e) {
System.out.println("unable to close statment" + e.toString());
}
out.close();
......
解决方案 »
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