一段java小程序的问题

Question

现在有两个数组，数组A里面装的是些部门信息（部门编号、部门名称），数组B里面有员工信息（部门编号、员工名称）我要打印出来的效果是：产品部--------
张三:LLLL
李四:LLLL
实施部--------
核武:LLLL
销售部--------
三五:LLLL
互补:LLLL
市场部--------
李婷:LLLL
人力资源部--------
小虎:LLLL
public static void main(String[] args) {
String []deptInfo=new String []{"1","产品部","2","实施部","3","销售部","4","市场部","5","人力资源部"};
String []employeeInfo=new String[]{"3","三五","3","互补","4","李婷","1","张三","1","李四","2","核武","5","小虎"};
String a=null;
for (int i = 0; i < deptInfo.length; i++) {

if(i%2==0){

  a=deptInfo[i];
  
  System.out.println(deptInfo[i+1]+"--------");
 }

for (int j = 0; j < employeeInfo.length; j++) {

if(j%2==0){

    if(a.equals(employeeInfo[j])){
    
     System.out.println(employeeInfo[j+1]+":LLLL");
    }

}

}

}

}不知道我代码哪里有问题，为什么打印员工信息的时候，都重复执行两遍。打印后效果如下产品部--------
张三:LLLL
李四:LLLL
张三:LLLL
李四:LLLL
实施部--------
核武:LLLL
核武:LLLL
销售部--------
三五:LLLL
互补:LLLL
三五:LLLL
互补:LLLL
市场部--------
李婷:LLLL
李婷:LLLL
人力资源部--------
小虎:LLLL
小虎:LLLL

Answer 1

for example
String []deptInfo=new String []{"1","产品部","2","实施部","3","销售部","4","市场部","5","人力资源部"};
String []employeeInfo=new String[]{"3","三五","3","互补","4","李婷","1","张三","1","李四","2","核武","5","小虎"};
String a=null;
for (int i = 0; i < deptInfo.length; i+=2) {
    a=deptInfo[i];
    System.out.println(deptInfo[i]+"--------");    for (int j = 0; j < employeeInfo.length-1; j+=2) {
        if(a.equals(employeeInfo[j])){
            System.out.println(employeeInfo[j+1]+":LLLL");
        }
    }
}

Answer 2

当下标为奇数时，a的值仍为上一次偶数的赋值，所以重复了。
如：当i=1时，a的值仍为0。
这是我改的
String []deptInfo=new String []{"1","产品部","2","实施部","3","销售部","4","市场部","5","人力资源部"};
String []employeeInfo=new String[]{"3","三五","3","互补","4","李婷","1","张三","1","李四","2","核武","5","小虎"};
String a=null;
for (int i = 0; i < deptInfo.length; i++) { if(i%2==0){ a=deptInfo[i];
 
System.out.println(deptInfo[i+1]+"--------");
}else
a=null;//当下标位置为部门名称时清空

for (int j = 0; j < employeeInfo.length; j++) { if(j%2==0){

if(a!=null)//判断是否为空
if(a.equals(employeeInfo[j])){
System.out.println(employeeInfo[j+1]+":LLLL");

} } }//a=null; 这里清空也行！ }
}

Answer 3

当下标为奇数时，a的值仍为上一次偶数的赋值，所以重复了。
如：当i=1时，a的值仍为0。
这是我改的 String []deptInfo=new String []{"1","产品部","2","实施部","3","销售部","4","市场部","5","人力资源部"};
String []employeeInfo=new String[]{"3","三五","3","互补","4","李婷","1","张三","1","李四","2","核武","5","小虎"};
String a=null;
for (int i = 0; i < deptInfo.length; i++) { if(i%2==0){ a=deptInfo[i];
 
System.out.println(deptInfo[i+1]+"--------");
}else
a=null;//当下标位置为部门名称时清空

for (int j = 0; j < employeeInfo.length; j++) { if(j%2==0){

if(a!=null)//判断是否为空
if(a.equals(employeeInfo[j])){
System.out.println(employeeInfo[j+1]+":LLLL");

} } }//a=null; 这里清空也行！ }
}

Answer 4

String strTemp="abcd";

StringBuffer buffer=new StringBuffer();

int strLength=strTemp.length()-1;//循环的总次数

int i=0;

while (i<strLength) {

if(i!=strLength-1) buffer.append(strTemp.substring(i,i+2)+",");

else buffer.append(strTemp.substring(i,i+2));

i++;
}
System.out.println(buffer);