请教 过滤器问题 麻烦哪位帮帮忙

Question

最近在弄 在线word编辑的一个东西  用的别人的控件. 其中有一个 OfficeServer.jsp 下面是我的web.xml 配置  里面配置里 *.jsp 过滤所有jsp 页面 但是我  OfficeServer.jsp这个页面不需要过滤 因为一过滤 它里面的 的 request对象 传值 会变成 struts2 里面的org.apache.struts2.dispatcher.multipart.MultiPartRequestWrapper  
而我需要的是 
org.apache.catalina.connector.RequestFacade 这个 
<!-- 定义Struts2的FilterDispathcer的Filter -->
<filter>
<filter-name>struts2</filter-name>
<filter-class>org.apache.struts2.dispatcher.FilterDispatcher</filter-class>
</filter>
<!-- FilterDispatcher用来初始化struts2并且处理所有的WEB请求。 -->
<filter-mapping>
<filter-name>struts2</filter-name>
<url-pattern>*.do</url-pattern>
</filter-mapping>
<filter-mapping>
<filter-name>struts2</filter-name>
<url-pattern>*.jsp</url-pattern>
</filter-mapping>
<filter-mapping>
<filter-name>struts2</filter-name>
<url-pattern>/struts/*</url-pattern>
</filter-mapping>
问题就是 只要 不过滤 OfficeServer.jsp  这个页面   
在filter-mapping里面配置 很多 包下面的jsp 这样是最坏的打算 还有其他的么??

Answer 1

<url-pattern>/*</url-pattern>
 

Answer 2

过滤器源代码
import org.apache.struts2.StrutsStatics;
import org.apache.struts2.dispatcher.Dispatcher;
import org.apache.struts2.dispatcher.mapper.ActionMapping;
import org.apache.struts2.dispatcher.ng.ExecuteOperations;
import org.apache.struts2.dispatcher.ng.InitOperations;
import org.apache.struts2.dispatcher.ng.PrepareOperations;import javax.servlet.*;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import java.io.IOException;
import java.util.List;
import java.util.regex.Pattern;/**
 * Handles both the preparation and execution phases of the Struts dispatching process.  This filter is better to use
 * when you don't have another filter that needs access to action context information, such as Sitemesh.
 */
public class StrutsPrepareAndExecuteFilter implements StrutsStatics, Filter {
    protected PrepareOperations prepare;
    protected ExecuteOperations execute;
protected List<Pattern> excludedPatterns = null;    public void init(FilterConfig filterConfig) throws ServletException {
        InitOperations init = new InitOperations();
        try {
            FilterHostConfig config = new FilterHostConfig(filterConfig);
            init.initLogging(config);
            Dispatcher dispatcher = init.initDispatcher(config);
            init.initStaticContentLoader(config, dispatcher);            prepare = new PrepareOperations(filterConfig.getServletContext(), dispatcher);
            execute = new ExecuteOperations(filterConfig.getServletContext(), dispatcher);
this.excludedPatterns = init.buildExcludedPatternsList(dispatcher);            postInit(dispatcher, filterConfig);
        } finally {
            init.cleanup();
        }    }    /**
     * Callback for post initialization
     */
    protected void postInit(Dispatcher dispatcher, FilterConfig filterConfig) {
    }    public void doFilter(ServletRequest req, ServletResponse res, FilterChain chain) throws IOException, ServletException {        HttpServletRequest request = (HttpServletRequest) req;
        HttpServletResponse response = (HttpServletResponse) res;        try {
            prepare.setEncodingAndLocale(request, response);
            prepare.createActionContext(request, response);
            prepare.assignDispatcherToThread();
if ( excludedPatterns != null && prepare.isUrlExcluded(request, excludedPatterns)) {
chain.doFilter(request, response);
} else {
request = prepare.wrapRequest(request);
ActionMapping mapping = prepare.findActionMapping(request, response, true);
if (mapping == null) {
boolean handled = execute.executeStaticResourceRequest(request, response);
if (!handled) {
chain.doFilter(request, response);
}
} else {
execute.executeAction(request, response, mapping);
}
}
        } finally {
            prepare.cleanupRequest(request);
        }
    }    public void destroy() {
        prepare.cleanupDispatcher();
    }
}

Answer 3

错了，不是一个版本的。sorry 

Answer 4

也不用那么麻烦啊    你可以直接用struts2的  struts.action.excludePattern属性来配置啊   比如你不需要struts2拦截/user/*.action  那么你就直接    struts.action.excludePattern=/user/*.action就ok了    在struts.xml里配置  或者struts-default.properties 都行

Answer 5

其实我都是只过滤   .action 很少去过滤所有

Answer 6

不管是在 struts.xml 里面配置 
<constant name="struts.action.excludePattern" value="OfficeServer.*"/>
或 <constant name="struts.action.excludePattern" value="/oa/OfficeServer.jsp"/>
或 <constant name="struts.action.excludePattern" value="/oa/*"/>还有struts属性文件里面配置 
struts.action.excludePattern=/oa/OfficeServer.jsp
等一下  都不行我现在只知道 在web.xml里面吧 <filter-mapping>
<filter-name>struts2</filter-name>
<url-pattern>*.jsp</url-pattern>
</filter-mapping>去掉才行的通

Answer 7

是的，你拦截了所有的jsp文件，你为什么要这样做？用struts2的话还是只拦截action的比较好要不就重写下过滤器
把那个类的源码改下就可以了，然后在web.xml中添加自己的过滤器

Answer 8

我自己写一个过滤器 拦截那个页面         <filter>
<filter-name>officeServer</filter-name>
<filter-class>com.zds.oa.filter.OfficeServerFilter</filter-class>
<init-param>
<param-name>encoding</param-name>
<param-value>utf-8</param-value>
</init-param>
</filter>
<filter-mapping>
<filter-name>officeServer</filter-name>
<url-pattern>/oa/OfficeServer.jsp</url-pattern>
</filter-mapping>已经进入过滤器了 但是怎么跳过 其他过滤器??? 
chain.doFilter(request, response); 过后还是去struts 里面去了

Answer 9

<url-pattern>/oa/OfficeServer.jsp</url-pattern>

Answer 10

额...   我自己弄好了  自定义一个 filter监听器 
在  oFilter
里面 request.getRequestDispatcher("/oa/OfficeServer.jsp").forward(request, response); 谢谢各位