spring整合quartz问题？

Question

本帖最后由 cxiyue 于 2013-07-11 16:06:32 编辑

Answer 1

配置如下<!-- 配置quartz -->
    <bean name="jobDetail01" class="org.springframework.scheduling.quartz.JobDetailBean">  
        <property name="jobClass">  
            <value>demo.Quartz.MyJob</value>
        </property>
        <property name="applicationContextJobDataKey">
         <value>applicationContext</value>
        </property>
        <property name="jobDataAsMap">
            <map>  
                <entry key="size" value="10"/>
            </map>
        </property>  
    </bean>
    
    <bean id="cronTrgger" class="org.springframework.scheduling.quartz.CronTriggerBean">
     <property name="jobDetail">  
            <ref bean="jobDetail01"/>
        </property>
        <property name="cronExpression" value="0/5 * * * * ?" />
    </bean>
      
    <bean id="scheduler" class="org.springframework.scheduling.quartz.SchedulerFactoryBean">  
        <property name="triggers">  
            <list>  
                <ref local="cronTrgger"/>
            </list>  
        </property>
        <property name="schedulerContextAsMap">
         <map>
         <entry key="timeout" value="30" />
         </map>
        </property>
        <property name="configLocation" value="classpath:quartz.properties" />
    </bean>

Answer 2

换成这个 jobDetail 就可以运行<bean id ="jobDetail02" 
     class="org.springframework.scheduling.quartz.MethodInvokingJobDetailFactoryBean">
     <property name="targetObject">
     <bean id="MyJob02" class="demo.Quartz.MyJob02" />
     </property>
     <property name="targetMethod" value="doWork"/>
     <property name="concurrent" value="false" />
    </bean><!--//可以正常运行 -->

Answer 3

用spring自带的定时调度   注解方式 @Scheduled(cron = "0 00 02 01 * ?")不用quartz

Answer 4

@Scheduled(cron = "0 * * * * MON-FRI")没有执行耶

Answer 5

要配置其他的吗
试了下  不执行   在service里试的    系统时间改为12号星期五