现在又两个项目,分别是test1和test2,怎么发布到同一个tomcat中(tomcat是本地的),然后以下面的方式访问:
http://localhost:8080/test1
http://localhost:8080/test2
知道的帮帮忙,不甚感激!!!!
http://localhost:8080/test1
http://localhost:8080/test2
知道的帮帮忙,不甚感激!!!!
调试欢乐多
at org.springframework.web.util.WebUtils.setWebAppRootSystemProperty(WebUtils.java:146)
at org.springframework.web.util.Log4jWebConfigurer.initLogging(Log4jWebConfigurer.java:118)
at org.springframework.web.util.Log4jConfigListener.contextInitialized(Log4jConfigListener.java:47)
at org.apache.catalina.core.StandardContext.listenerStart(StandardContext.java:3934)
at org.apache.catalina.core.StandardContext.start(StandardContext.java:4429)
at org.apache.catalina.core.ContainerBase.start(ContainerBase.java:1045)
at org.apache.catalina.core.StandardHost.start(StandardHost.java:722)
at org.apache.catalina.core.ContainerBase.start(ContainerBase.java:1045)
at org.apache.catalina.core.StandardEngine.start(StandardEngine.java:443)
at org.apache.catalina.core.StandardService.start(StandardService.java:516)
at org.apache.catalina.core.StandardServer.start(StandardServer.java:710)
at org.apache.catalina.startup.Catalina.start(Catalina.java:583)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25)
at java.lang.reflect.Method.invoke(Method.java:597)
at org.apache.catalina.startup.Bootstrap.start(Bootstrap.java:288)
at org.apache.catalina.startup.Bootstrap.main(Bootstrap.java:413)
http://localhost:8080/test2
<param-name>webAppRootKey</param-name>
<param-value>app1.root</param-value>
</context-param><context-param>
<param-name>webAppRootKey</param-name>
<param-value>app2.root</param-value>
</context-param>