HttpServletRequest的方法应用

Question

http://localhost:8080/grea/usercenter/buss/sellList.htm?page=1,请求路径是这个,怎么拿到全部?我最多也就拿到的是http://localhost:8080/grea?page=1,这个怎么处理,请高手解决一下

Answer 1

String scheme = request.getScheme(); 
out.println("scheme = " + scheme + "<br />");  
String serverName = request.getServerName();
out.println("serverName = " + serverName + "<br />"); 
int serverPort = request.getServerPort(); 
out.println("serverPort = " + serverPort + "<br />"); 
String contextPath = request.getContextPath(); 
out.println("contextPath = " + contextPath + "<br />"); 
String servletPath = request.getServletPath(); 
out.println("servletPath = " + servletPath + "<br />"); 
String queryString = request.getQueryString();
out.println("queryString = " + queryString + "<br />");
String requestURI = request.getRequestURI();
out.println("requestURI = " + requestURI + "<br />"); 
String info=request.getPathInfo();
out.println("info = " + info + "<br />");
String pageUrl=null;
if(request.getQueryString()!=null){
pageUrl=request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"?"+request.getQueryString();
}else{
pageUrl=request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path;
}
out.println("pageUrl = " + pageUrl + "<br />");
用这些方法测试得到的是
scheme = http
serverName = localhost
serverPort = 8080
contextPath = /grea
servletPath = /jsp/usercenter/business/merchant_record_list.jsp
queryString = page=1
requestURI = /grea/jsp/usercenter/business/merchant_record_list.jsp
info = null
pageUrl = http://localhost:8080/grea?page=1
就少了/usercenter/buss/sellList.htm这一段