Struts2调用业务方法报空指针

这是Struts.xml
<struts>
<constant name="struts.devMode" value="true"></constant>
<package name="IndexAction" namespace="/" extends="struts-default">
<action name="indexAction" class="com.demo.action.IndexAction" method="getAllGoods">
<result name="index">/index.jsp</result>
</action>
</package>
</struts>    
这是Action
@Controller("indexAction")
@Scope("prototype")public class IndexAction extends ActionSupport implements SessionAware{
@Autowired
private GoodsBiz goodsBiz;
public GoodsBiz getGoodsBiz() {
return goodsBiz;
}
@Resource(name="goodsBiz")
public void setGoodsBiz(GoodsBiz goodsBiz) {
this.goodsBiz = goodsBiz;
} private Map<String,Object> session=new HashMap<String, Object>(); public Map<String, Object> getSession() {
return session;
}
public void setSession(Map<String, Object> arg0) {
this.session=session;
}

private int count; public int getCount() {
return count;
}
public void setCount(int count) {
this.count = count;
}

public String getAllGoods(){
// try {
    List listGoods = goodsBiz.getAllGoods();  //出错
count=listGoods.size();
session.put("listGoods", listGoods);
// } catch (Exception e) {
// System.out.println(e.getMessage());
// }
System.out.println("test_Ok");
return "index";
}
这是beans.xml
<beans
xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:p="http://www.springframework.org/schema/p"
xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:aop="http://www.springframework.org/schema/aop"
xsi:schemaLocation="http://www.springframework.org/schema/beans 
http://www.springframework.org/schema/beans/spring-beans-2.5.xsd 
http://www.springframework.org/schema/tx 
http://www.springframework.org/schema/tx/spring-tx-2.5.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-2.5.xsd 
http://www.springframework.org/schema/aop
http://www.springframework.org/schema/aop/spring-aop-2.5.xsd">
<aop:aspectj-autoproxy/>
<context:component-scan base-package="com.demo" />
 
<bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalEntityManagerFactoryBean">
<property name="persistenceUnitName" value="demo" />
</bean>
<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
<property name="entityManagerFactory" ref="entityManagerFactory" />
</bean>
<tx:annotation-driven transaction-manager="transactionManager" /></beans>
这是Dao实现
@Service("goodsDao")
@Transactional
public class GoodsDaoImpl implements GoodsDao{
@PersistenceContext protected EntityManager em;

public List getAllGoods() {
Query query =  em.createQuery("from Goods g");
return query.getResultList();
}}
这事业务实现biz
@Service("goodsBiz")
@Transactional
public class GoodsBizImpl implements GoodsBiz {

private GoodsDao goodsDao;
public GoodsDao getGoodsDao() {
return goodsDao;
}
@Resource(name="goodsDao") 
public void setGoodsDao(GoodsDao goodsDao) {
this.goodsDao = goodsDao;
}
public List getAllGoods() {
return goodsDao.getAllGoods();
}
这是web.xml
<listener>
      <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
    </listener

<context-param>        
<param-name>contextConfigLocation</param-name>
<param-value>classpath:beans.xml</param-value>         <!-- 自定义路径 -->
</context-param>
    
    <filter>
     <display-name>jpaFilter</display-name>
     <filter-class> org.springframework.orm.jpa.support.OpenEntityManagerInViewFilter </filter-class>
    </filter>  <welcome-file-list>
    <welcome-file>index.jsp</welcome-file>
  </welcome-file-list>
  <filter>
   <filter-name>struts2</filter-name>
   <filter-class>
   org.apache.struts2.dispatcher.ng.filter.StrutsPrepareAndExecuteFilter
   </filter-class>
  </filter>
  <filter-mapping>
   <filter-name>struts2</filter-name>
   <url-pattern>/*</url-pattern>
  </filter-mapping></web-app>
代码执行到Action红色那行代码是就报空指针，调用不到biz的方法？怎么回事