求个java实现的webservice返回xml的例子代码

Question

.......VC程序员，无任何web开发经验，赶鸭子上架只能学了目前只想实现一个webservice，读取数据库然后将检索结果构造成xml形式return，客户端自己再解析出内容，很简单的入门级别类，JDBC操作无问题，希望有例子的朋友指点下代码，谢了

Answer 1

如果不涉及到SOAP，用Servlet/JSP直接就可以做了。

Answer 2

import javax.jws.WebMethod;
import javax.jws.WebService;
import javax.jws.soap.SOAPBinding;
import javax.xml.ws.Endpoint;@WebService(targetNamespace = "http://jdk.study.hermit.org/client")
@SOAPBinding(style = SOAPBinding.Style.RPC)
public class Hello
{
@WebMethod
public String sayHello(String name)
{
return "hello:" + name;
}

public static void main(String[] args)
{
Endpoint.publish("http://localhost:80/hello", new Hello());
}
}
运行这个程序,然后访问你本机:http://localhost:80/hello?wsdl,可以看到如下页面<?xml version="1.0" encoding="UTF-8"?><definitions xmlns="http://schemas.xmlsoap.org/wsdl/" xmlns:tns="http://jdk.study.hermit.org/client" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:soap="http://schemas.xmlsoap.org/wsdl/soap/" targetNamespace="http://jdk.study.hermit.org/client" name="HelloService">
  <types></types>
  <message name="sayHello">
    <part name="arg0" type="xsd:string"></part>
  </message>
  <message name="sayHelloResponse">
    <part name="return" type="xsd:string"></part>
  </message>
  <portType name="Hello">
    <operation name="sayHello" parameterOrder="arg0">
      <input message="tns:sayHello"></input>
      <output message="tns:sayHelloResponse"></output>
    </operation>
  </portType>
  <binding name="HelloPortBinding" type="tns:Hello">
    <soap:binding style="rpc" transport="http://schemas.xmlsoap.org/soap/http"></soap:binding>
    <operation name="sayHello">
      <soap:operation soapAction=""></soap:operation>
      <input>
        <soap:body use="literal" namespace="http://jdk.study.hermit.org/client"></soap:body>
      </input>
      <output>
        <soap:body use="literal" namespace="http://jdk.study.hermit.org/client"></soap:body>
      </output>
    </operation>
  </binding>
  <service name="HelloService">
    <port name="HelloPort" binding="tns:HelloPortBinding">
      <soap:address location="http://localhost/hello"></soap:address>
    </port>
  </service>
</definitions>

Answer 3

刚才只是如何使用WS,关于XML解析,自己去查DOM4J文档或去网上搜.大把大把的.

Answer 4

import javax.jws.WebMethod;
import javax.jws.WebService;
import javax.jws.soap.SOAPBinding;
import javax.xml.ws.Endpoint;@WebService(targetNamespace = "http://jdk.study.hermit.org/client")
@SOAPBinding(style = SOAPBinding.Style.RPC)
public class Hello
{
    @WebMethod
    public String sayHello(String name)
    {
        return "hello:" + name;
    }
    
    public static void main(String[] args)
    {
        Endpoint.publish("http://localhost:80/hello", new Hello());
    }
}同意3 楼