为什么我用HttpClient访问这样的url (http://10.0.0.32/appOper/dcAppStyle!monitorAppStyle.action?applicaiton=9527)时 返回的状态码为:302 ,但我 在url里直接写 一个类似 (http://10.0.0.32/jsp/app/showApp.jsp) 这样的 页面 能返回正确的结果.. 是不是HttpClient不能访问 action带参数的 这样的URL呀...还望各位 大虾 帮下忙
调试欢乐多
但是你最好直接请求某个action
post的参数通过
HttpMethodParams p = new HttpMethodParams();
p.setParameter("","");
来设置!
String url = "http://10.0.0.32/appOper/dcAppStyle!monitorAppStyle.action";
PostMethod post = new PostMethod(url); HttpMethodParams p = new HttpMethodParams();
p.setParameter("applicaiton","9527"); return post;
我怎样把参数 和post请求联系起来呀
method.setParams(p);
返回的状态还是302public static void main(String[] args) { try {
HttpClient client = new HttpClient(); HttpMethod method = getPostMethod(); // 使用POST方式提交数据
int statusCode = client.executeMethod(method); // 打印服务器返回的状态
String state = method.getStatusLine().toString();
System.out.println("服务器返回的状态:" +state +" 状态码:" +statusCode); // 打印结果页面
String response = new String(method.getResponseBodyAsString()
.getBytes("gb2312"));
// 打印返回的信息
System.out.println("结果页面" + response); method.releaseConnection();
} catch (Exception e) {
e.printStackTrace();
}
}private static HttpMethod getPostMethod() { String url = "http://10.0.0.32/appOper/dcAppStyle!monitorAppStyle.action";
HttpMethodParams p = new HttpMethodParams();
p.setParameter( "applicaiton ", "9527 "); HttpMethod post = new PostMethod(url);
post.setParams(p); return post; }