hibernate 使用discriminator时报错

Question

<hibernate-mapping>
<class name="code.User" table="user" catalog="sample" discriminator-value="not null"> <id name="id" type="java.lang.Integer">
<column name="Id" />
<generator class="identity" />
</id> <property name="age" type="int">
<column name="age" not-null="true" />
</property> <property name="firstname" type="string">
<column name="firstname" length="20" not-null="true" />
</property> <property name="lastname" type="string">
<column name="lastname" length="20" not-null="true" />
</property>
<discriminator column="type" type="int" not-null="true"/> <subclass name="code.AddressUser" discriminator-value="0">
<property name="address" column="address" />
<property name="zipcode" column="zipcode" />
</subclass> <subclass name="code.TelUser" discriminator-value="1">
<property name="tel" column="tel" />
</subclass> </class>
</hibernate-mapping>当我一添加discriminator 就报错The content of element type "class" must match

Answer 1

贴个示例你看下
<class name="cn.com.leadfar.oa.model.Party" table="t_party" discriminator-value="X">
<id name="id">
<generator class="native"/>
</id>
<discriminator column="party_type" type="char"></discriminator>
<property name="name"/>
<property name="description"/>
<many-to-one name="parent" column="pid"/>
<set name="children" lazy="extra" inverse="true" order-by="id">
<key column="pid"/>
<one-to-many class="cn.com.leadfar.oa.model.Party"/>
<filter name="no_contain_person" condition="party_type != 'P'"></filter>
</set>
<subclass name="cn.com.leadfar.oa.model.Company" discriminator-value="C">
<property name="tel"/>
<property name="fax"/>
<property name="address"/>
<property name="postcode"/>
<property name="site"/>
<property name="email"/>
<property name="industry"/>
</subclass>
<subclass name="cn.com.leadfar.oa.model.Department" discriminator-value="D">
<property name="tel"/>
<property name="snumber"/>
</subclass>
<subclass name="cn.com.leadfar.oa.model.Person" discriminator-value="P">
<property name="snumber"/>
<property name="sex"/>
<property name="phone"/>
<property name="duty"/>
<property name="address"/>
<property name="qq"/>
<property name="msn"/>
<property name="email"/>
<one-to-one name="user"/>
</subclass>
<subclass name="cn.com.leadfar.oa.model.Position" discriminator-value="S">
</subclass>
</class>
<filter-def name="no_contain_person"></filter-def>

Answer 2

都指明type="int"
为什么discrimintor-value=""not null"

Answer 3

找到原因了，把discriminator放在定义id的后面就可以了