page = dao.find("from TUser",1,100);
if(page!=null){
return SUCCESS;
}else{
return INPUT;
}
<action name="findAllUser" class="userAction" method="findAll">
<result type="json">
<param name="root">page</param>
</result>
</action>如果没有经过STRUTS的解析JSON,就只会产生一条SQL语句
如果经过解析JSON,就会产生N多条SQL语句TUser这个对象关联了很多对象
<set name="TUsergroupusers" inverse="true" lazy="true">
<key>
<column name="USID" precision="22" scale="0" not-null="true" />
</key>
<one-to-many class="com.xaec.model.TUsergroupuser" />
</set>
<set name="TUserroles" inverse="true" lazy="true">
<key>
<column name="USID" precision="22" scale="0" not-null="true" />
</key>
<one-to-many class="com.xaec.model.TUserrole" />
</set>
<set name="TUserfieldpers" inverse="true" lazy="true">
<key>
<column name="USID" precision="22" scale="0" not-null="true" />
</key>
<one-to-many class="com.xaec.model.TUserfieldper" />
</set>
<set name="TUserfuns" inverse="true" lazy="true">
<key>
<column name="USID" precision="22" scale="0" not-null="true" />
</key>
<one-to-many class="com.xaec.model.TUserfun" />
</set>
if(page!=null){
return SUCCESS;
}else{
return INPUT;
}
<action name="findAllUser" class="userAction" method="findAll">
<result type="json">
<param name="root">page</param>
</result>
</action>如果没有经过STRUTS的解析JSON,就只会产生一条SQL语句
如果经过解析JSON,就会产生N多条SQL语句TUser这个对象关联了很多对象
<set name="TUsergroupusers" inverse="true" lazy="true">
<key>
<column name="USID" precision="22" scale="0" not-null="true" />
</key>
<one-to-many class="com.xaec.model.TUsergroupuser" />
</set>
<set name="TUserroles" inverse="true" lazy="true">
<key>
<column name="USID" precision="22" scale="0" not-null="true" />
</key>
<one-to-many class="com.xaec.model.TUserrole" />
</set>
<set name="TUserfieldpers" inverse="true" lazy="true">
<key>
<column name="USID" precision="22" scale="0" not-null="true" />
</key>
<one-to-many class="com.xaec.model.TUserfieldper" />
</set>
<set name="TUserfuns" inverse="true" lazy="true">
<key>
<column name="USID" precision="22" scale="0" not-null="true" />
</key>
<one-to-many class="com.xaec.model.TUserfun" />
</set>
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE struts PUBLIC "-//Apache Software Foundation//DTD Struts Configuration 2.1//EN"
"http://struts.apache.org/dtds/struts-2.1.dtd"><struts>
<package name="system/qzgl" extends="json-default" namespace="/system/qzgl">
<action name="*qzxxAction" class="qzxxAction" method="{1}">
<result type="json">
<param name="excludeProperties">
<!-- 不会被序列化的Action属性 -->
qzxxList.*.qzries
</param>
</result>
</action>
<action name="*qzryAction" class="qzryAction" method="{1}">
<result type="json">
<param name="excludeProperties">
<!-- 不会被序列化的Action属性 -->
qzryList.*.sysUsers.jsries,qzryList.*.sysUsers.qzries,qzryList.*.sysUsers.dwxx.sysUserses
</param>
</result>
</action>
</package>
</struts>
在struts配置文件中做处理,不知楼主能理解否?过滤到不需要序列化的属性,就不会出现多余的sql
這是我的TUser的內容
private Set TUsergroupusers = new HashSet(0); private String loginPassword; private Set TUserroles = new HashSet(0); private Set TUserfieldpers = new HashSet(0); private Set TUserfuns = new HashSet(0);
怎麼攔截不生效?