<servlet>
      <servlet-name>config</servlet-name>
      <jsp-file>/wwwroot/Config.jsp</jsp-file>
      <init-param>
          <param-name>test</param-name>
          <param-value>It's a test</param-value>
      </init-param>
  </servlet>
  <servlet-mapping>
    <servlet-name>config</servlet-name>
    <url-pattern>/wwwroot/Config.jsp</url-pattern>  </servlet-mapping>
    <%
        Enumeration e = config.getInitParameterNames();
        String paramName;
        String paramValue;
        
        while (e.hasMoreElements()) {
            paramName = (String)e.nextElement();
            paramValue = config.getInitParameter(paramName);
            
            out.println("param-name:" + paramName + "<br>");
            out.println("param-value:" + paramValue + "<br>");
        }
        out.println("servlet name:" + config.getServletName());
    %>
    我想问的问题,上面那个WEB。XML文件中的路径怎么配置。我运行起来404 ERROR