<servlet>
<servlet-name>config</servlet-name>
<jsp-file>/wwwroot/Config.jsp</jsp-file>
<init-param>
<param-name>test</param-name>
<param-value>It's a test</param-value>
</init-param>
</servlet>
<servlet-mapping>
<servlet-name>config</servlet-name>
<url-pattern>/wwwroot/Config.jsp</url-pattern> </servlet-mapping>
<%
Enumeration e = config.getInitParameterNames();
String paramName;
String paramValue;
while (e.hasMoreElements()) {
paramName = (String)e.nextElement();
paramValue = config.getInitParameter(paramName);
out.println("param-name:" + paramName + "<br>");
out.println("param-value:" + paramValue + "<br>");
}
out.println("servlet name:" + config.getServletName());
%>
我想问的问题,上面那个WEB。XML文件中的路径怎么配置。我运行起来404 ERROR
<servlet-name>config</servlet-name>
<jsp-file>/wwwroot/Config.jsp</jsp-file>
<init-param>
<param-name>test</param-name>
<param-value>It's a test</param-value>
</init-param>
</servlet>
<servlet-mapping>
<servlet-name>config</servlet-name>
<url-pattern>/wwwroot/Config.jsp</url-pattern> </servlet-mapping>
<%
Enumeration e = config.getInitParameterNames();
String paramName;
String paramValue;
while (e.hasMoreElements()) {
paramName = (String)e.nextElement();
paramValue = config.getInitParameter(paramName);
out.println("param-name:" + paramName + "<br>");
out.println("param-value:" + paramValue + "<br>");
}
out.println("servlet name:" + config.getServletName());
%>
我想问的问题,上面那个WEB。XML文件中的路径怎么配置。我运行起来404 ERROR
解决方案 »
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这个不就是你配置的访问路径吗?