<form id="f1" onsubmit="return validateForm();" action="refundment.do" method="post">
申请退款:
<br/>
<div>
请填写您申请的账号:<input type="text" name="accountNo" onblur="validateAccountNo(this)";/>
<span id="accountNo_error" style="color: red"></span>
</div>
<div>
<input type="submit" value="提交"/>
</div>
</form>点击“提交”时候就直接提交到”refundment.do“喽onsubmit="return validateForm();"这个都没起到作用怎么办呀!谢谢大家指点指点!
申请退款:
<br/>
<div>
请填写您申请的账号:<input type="text" name="accountNo" onblur="validateAccountNo(this)";/>
<span id="accountNo_error" style="color: red"></span>
</div>
<div>
<input type="submit" value="提交"/>
</div>
</form>点击“提交”时候就直接提交到”refundment.do“喽onsubmit="return validateForm();"这个都没起到作用怎么办呀!谢谢大家指点指点!
function validateForm(){
var form = document.getElementById('f1');
var b = validateAccountNo(form['accountNo']) & validateAccountName(form['accountName']) &
validateMoney(form['money']& validateTuikuandateform['tuikuandate'])
return b == 0 ? false : true;
}
var b = validateAccountNo(form['accountNo']) & validateAccountName(form['accountName']) &
validateMoney(form['money']& validateTuikuandateform['tuikuandate'])
下面alert(b);
看看b到底是个什么东西应该是这里有问题
写在Button里,然后在validateAccountNo函数写出跳转的Action
应该是这样的黏贴和复制的时候弄错了。。
validateMoney(form['money']) & validateTuikuandate (form['tuikuandate'])谢谢大家啦!