大家好,这道题我不太明白,求辅导:
public static void main(String[] args) {
System.out.println("start");
new Thread(new Runnable() {
public void run() {
System.out.println("step2");
}
}).start();
System.out.println("step1");
new Thread(new Runnable() {
public void run() {
System.out.println("step3");
}
}).start();
System.out.println("end");
}另外,如果我想输出 start step2 step1 step3 end的话怎么弄?
public static void main(String[] args) {
System.out.println("start");
new Thread(new Runnable() {
public void run() {
System.out.println("step2");
}
}).start();
System.out.println("step1");
new Thread(new Runnable() {
public void run() {
System.out.println("step3");
}
}).start();
System.out.println("end");
}另外,如果我想输出 start step2 step1 step3 end的话怎么弄?
public static void main(String[] args) throws Exception {
System.out.println("start"); Thread t1 = new Thread(new Runnable() {
public void run() {
System.out.println("step2");
}
});
t1.start();
t1.join(); System.out.println("step1"); Thread t2 = new Thread(new Runnable() {
public void run() {
System.out.println("step3");
}
});
t2.start();
t2.join();
System.out.println("end"); }
}
System.out.println("start");Thread t1 = new Thread(new Runnable() {
public void run() {
System.out.println("step2");
}
});
t1.start();
t1.join();//用join方法
System.out.println("step1");
Thread t2 = new Thread(new Runnable() {
public void run() {
System.out.println("step3");
}
});
t2.start();
t2.join();//
System.out.println("end");
线程优先级也是 在许多次执行状态下,优先执行级别高的,这都是宏观状态阿
级别低的线程还是能分到CPU时间片,只不过概率 更低阿
这个 无法控制