hibernate中用uuid算法生成主键怎样配置?

解决方案 »

  1.   

    <hibernate-mapping>
    <class name="cn.data.jsytjxx.Jsytjxx"
    table="B_YW_JSYTJXX" schema="ADMINISTRATOR">
    <id name="systemid" type="java.lang.String">
    <column name="SYSTEMID" length="50" />
    <generator class="uuid.hex"></generator>
    </id>
    <property name="tjlsh" type="java.lang.String">
    <column name="TJLSH" length="20" not-null="true" />
    </property>
    </class>
    </hibernate-mapping>
      

  2.   

            <id name="主键属性" type="java.lang.String">
                <column name="对应列" length="32" />
                <generator class="uuid.hex" />
            </id>