XML读取

Question

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE Order_CRM_root>
<SiebelMessage MessageId="1-C5E7D4" IntObjectName="Order Entry (Billing)" MessageType="Integration Object" IntObjectFormat="Siebel Hierarchical">
<ns0:ListOfOrderEntryBilling xmlns:ns0="http://www.siebel.com/xml/Order Entry (Billing)">
<OrderEntry-OrdersIo>
<OrderNumber>1-1BR0-6114</OrderNumber>
在Java里面这样读，哪里错了？？？
List list = document.selectNodes("//SiebelMessage/ns0:ListOfOrderEntryBilling/OrderEntry-OrdersIo/OrderNumber");急

Answer 1

把xml文件贴完全，错误信息，也贴出来

Answer 2

xml文件太大了，提示找不到类

Answer 3

Exception in thread "main" java.lang.NoClassDefFoundError: org/jaxen/NamespaceContext
at org.dom4j.DocumentFactory.createXPath(DocumentFactory.java:230)
at org.dom4j.tree.AbstractNode.createXPath(AbstractNode.java:207)
at org.dom4j.tree.AbstractNode.selectNodes(AbstractNode.java:164)
at test.CopyXML.copyFile(CopyXML.java:46)
at test.CopyXML.main(CopyXML.java:29)

Answer 4

private String file;
public static void main(String[] args) {
CopyXML cxml = new CopyXML();

cxml.copyFile("1203101_1-1BR0-6114_.xml");
}

public void copyFile(String xmlFilePath){

String filePath = null;
if(xmlFilePath == null || "".equals(xmlFilePath.trim())){
filePath = file;
}else{
filePath = xmlFilePath;
}
System.out.println(filePath);
try {
ClassLoader classLoader = Thread.currentThread().getContextClassLoader();
InputStream is = classLoader.getResourceAsStream(filePath);
Document document = new SAXReader().read(is);

List list = document.selectNodes("//SiebelMessage/ns0:ListOfOrderEntryBilling/OrderEntry-OrdersIo/OrderNumber");
for(Iterator iter=list.iterator();iter.hasNext();){
Element elementOrderNo = (Element)iter.next();
String orderNo = elementOrderNo.getText();
System.out.println(orderNo);
}
} catch (DocumentException e) {
// TODO 自动生成 catch 块
e.printStackTrace();
}
}
}