xfire 调用带有用户名密码的webserivce如何写

Question

Client c = new Client(new URL("http://www.webxml.com.cn/WebServices/IpAddressSearchWebService.asmx?wsdl"));
Object[] results = c.invoke("getVersionTime", new Object[0]);

Answer 1

org.codehaus.xfire.fault.XFireFault: An error was discovered processing the <wsse:Security> header
报此异常，c.setProperty(CommonsHttpMessageSender.HTTP_PROXY_USER, "aaa");  c.setProperty(CommonsHttpMessageSender.HTTP_PROXY_PASS, "bbb"); 

Answer 2

xfire清楚,下面是AXIS2的写法,针对wss4j usertoken用户名和密码验证 String path = axis2.xml路径
QName name1 = new QName(命名空间, 方法名);
ConfigurationContext configContext = ConfigurationContextFactory.createConfigurationContextFromFileSystem(path, "");
RPCServiceClient serviceClient = new RPCServiceClient(configContext,null);
SOAP11Factory factory = new SOAP11Factory();
OMNamespace SecurityElementNamespace = factory.createOMNamespace("http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-secext-1.0.xsd","wsse");
OMElement usernameTokenEl = factory.createOMElement("UsernameToken",SecurityElementNamespace);
OMElement usernameEl = factory.createOMElement("Username",SecurityElementNamespace);
OMElement passwordEl = factory.createOMElement("Password",SecurityElementNamespace);
OMElement actionEl = factory.createOMElement("Action",SecurityElementNamespace);
passwordEl.addAttribute(factory.createOMAttribute("Type",null,
"http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-username-token-profile-1.0#PasswordText"));
usernameEl.setText(用户名);
passwordEl.setText(密码);
usernameTokenEl.addChild(usernameEl);
usernameTokenEl.addChild(passwordEl);
usernameTokenEl.addChild(actionEl);
SOAPHeaderBlockImpl block = new SOAP11HeaderBlockImpl("Security",SecurityElementNamespace, factory);
block.addChild(usernameTokenEl);
serviceClient.addHeader(block);

Answer 3

http://www.myexception.cn/web/679163.html
希望可以帮到你