<?xml version="1.0"?><!DOCTYPE hibernate-mapping PUBLIC
"-//Hibernate/Hibernate Mapping DTD 2.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-2.0.dtd"><hibernate-mapping>
<class
name="ab.tiezi"
table="tiezi"
dynamic-update="false"
dynamic-insert="false"
> <id
name="unid"
column="unid"
type="long"
>
<generator class="native">
</generator>
</id> <property
name="biaoti"
type="java.lang.String"
update="true"
insert="true"
column="biaoti"
length="20"
/>
<property
name="neirong"
type="java.lang.String"
update="true"
insert="true"
column="neirong"
length="20"
/>
</class>
</hibernate-mapping>其中的unid是你必须在类中的get set方法 ,
"-//Hibernate/Hibernate Mapping DTD 2.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-2.0.dtd"><hibernate-mapping>
<class
name="ab.tiezi"
table="tiezi"
dynamic-update="false"
dynamic-insert="false"
> <id
name="unid"
column="unid"
type="long"
>
<generator class="native">
</generator>
</id> <property
name="biaoti"
type="java.lang.String"
update="true"
insert="true"
column="biaoti"
length="20"
/>
<property
name="neirong"
type="java.lang.String"
update="true"
insert="true"
column="neirong"
length="20"
/>
</class>
</hibernate-mapping>其中的unid是你必须在类中的get set方法 ,
解决方案 »
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