要调用这个servlet,在tomcat5.0中要做那些设置(附代码)?

Question

我觉的你的WEB.XML是不是配置正确了?贴出来看看...

Answer 1

qyzj_wanghx(原啸天):就是web.xml的问题,但又不知道怎么改?要加那些内容才可以?

Answer 2

在web.xml中贴加如下   
<servlet>
       <servlet-name>Redirect</servlet-name>
   <servlet-class>从class开始的Redirect类的路径</servlet-class>
   </servlet>
   <servlet-mapping>
       <servlet-name>Redirect</servlet-name>
   <url-pattern你所要url的路径</url-pattern>
   </servlet-mapping>

Answer 3

<url-pattern>你所要url的路径</url-pattern>

Answer 4

举个例子：如果目标是这样访问：HelloWorld存放与classes下面
http://localhost:8080/debug/servlet/HelloWorld
web.xml加入：
<servlet>
<servlet-name>HelloWorld</servlet-name>
<servlet-class>HelloWorld</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>HelloWorld</servlet-name>
<url-pattern>/servlet/HelloWorld</url-pattern>
</servlet-mapping>
你再试试。

Answer 5

确保你的class文件无误之后在WEB.xml里配置如下
    <servlet>
        <servlet-name>whl</servlet-name>
        <servlet-class>ServletsRule</servlet-class>
    </servlet>
   <servlet-mapping>
        <servlet-name>whl</servlet-name>
        <url-pattern>/whl</url-pattern>
   </servlet-mapping>
 grantbb(小兵) 已经讲得很清楚了。

Answer 6

你要到web.xml 文件中配置
 <servlet>
        <servlet-name>Redirect </servlet-name>
        <servlet-class>Redirect </servlet-class>
    </servlet>
   <servlet-mapping>
        <servlet-name>Redirect</servlet-name>
        <url-pattern>/Redirect</url-pattern>
   </servlet-mapping>

Answer 7

源码如下(不会有错吧?):
------------------------------------------------------
package Redirect;
import java.io.*;
import java.util.*;
import javax.servlet.http.*;
import javax.servlet.*;
public class Redirect extends HttpServlet{
public void doGet(
HttpServletRequest req,
HttpServletResponse res
)throws ServletException,IOException
{
res.sendRedirect("http://localhost:8080");
}
public Redirect(){}
}