大家进来看一下，如何实现http接口

Question

没有明白你的问题，什么叫http接口？URL吗？

Answer 1

想直接调用远端的servlet
用java.net.HttpURLConnection 
或是其他方法

Answer 2

你可以先看看这篇文章http://www.cn-java.com/target/news.php?news_id=2217

Answer 3

谢谢weimenren(愚人码头) 我现在，定义了URL
      URL url = new URL("http://localhost/smsweb/testservlet1");
建立了连接
      HttpURLConnection connection = (HttpURLConnection) url.openConnection();
      connection.setRequestMethod("POST");如何才能调用testservlet1中的doPost方法
并传参数过去，使testservlet1通过request.getParameter("xxx")的方法得到参数？

Answer 4

改了一下代码
      URL url = new URL("http://localhost/smsweb/testservlet1");
      connection = (HttpURLConnection) url.openConnection();
      connection.setRequestMethod("POST");
      connection.setDoOutput(true);
      PrintWriter out = new PrintWriter(connection.getOutputStream());      String name = "result=1";
      out.println(name);
      out.close();
好像没有起到直接调用
http://localhost/smsweb/testservlet1?result=1
的作用，呵呵
哪位大侠能指点1，2

Answer 5

以下是我的一段例子：
  public String sendSMS()
  {
    String strResult = "01";
    try
    {
      if(BusinessType.substring(0,1).equals("0"))
      {          SMSContent = SMS ;
      }
      StringBuffer sb = new StringBuffer("http://211.139.140.164:13083/cgi-bin/sendsms?");
  //    StringBuffer sb = new StringBuffer("http://192.168.0.4:13083/cgi-bin/sendsms?");
      sb.append("username=" + URLEncoder.encode(SpName, "UTF-8"));
      sb.append("&password=" + URLEncoder.encode(SpPassword, "UTF-8"));
      sb.append("&from=" + FromMobile);
      sb.append("&to=" + ToMobile);
      if(Sub.trim().length() > 0)
      {
        sb.append("&sub=" + Sub);
      }
      sb.append("&dcs=65536");
      sb.append("&sendtype=" + SendType);
      if(KeyWord.trim().length() > 0)
      {
        sb.append("&keyword=" +  URLEncoder.encode(KeyWord, "UTF-8")); 
      }
      if(FeeCode.trim().length() > 0)
      {
        sb.append("&feecode=" + URLEncoder.encode(FeeCode, "UTF-8")); 
      }
      if(SMSContent.trim().length() > 0)
      {
        sb.append("&text=" + URLEncoder.encode(SMSContent, "UTF-8"));
      }
      URL url = new URL(sb.toString());
      BufferedReader in = new BufferedReader(
        new InputStreamReader(
        url.openStream()));
      String inputline = in.readLine();
      if(inputline != null)
      {
        loginstance.log("发送短信,"+sb.toString()+ " " + inputline);
      }
      in.close();      if(!(inputline.equals("success:1,failed:0")))
      {
        loginstance.log("发送短信失败,"+sb.toString()+ " " + inputline);
        loginstance.error("发送短信失败,"+sb.toString()+ " " + inputline);
        strResult = "FF";
      }
    }
    catch(Exception e)
    {
      loginstance.log(e,"发送短信失败," + Request);
      loginstance.error(e,"发送短信失败," + Request);
      strResult = "FF";
    }
    return strResult;
  }

Answer 6

创建了URL以后，你需要
URL url = new URL(urlString);
BufferedReader in = new BufferedReader(
        new InputStreamReader(
        url.openStream()));
而后：String inputline = in.readLine();

Answer 7

谢谢
我把代码改成
   URL url = new URL("http://localhost/smsweb/testservlet1?result=1");
   connection = (HttpURLConnection) url.openConnection();
   connection.setRequestMethod("POST");
   connection.setDoOutput(true);   BufferedReader in = new BufferedReader(new InputStreamReader(connection.
       getInputStream()));
   in.close();
就好了

Answer 8

URL url = new URL("http://localhost/smsweb/testservlet1?result=2");   BufferedReader in = new BufferedReader(new InputStreamReader(url.openStream()));
   in.close();这样更加精简点，活活