求ldap获取域用户 ldap需求 解决方案 » 免费领取超大流量手机卡,每月29元包185G流量+100分钟通话, 中国电信官方发货 SearchControls constraints = new SearchControls();constraints.setSearchScope(SearchControls.SUBTREE_SCOPE);NamingEnumeration<?> en = dirContext.search(root, "cn=" + usr, constraints);//cn改为你的域名应该就行了。 我测试的域名是:2003.com,至于域管理员账号和密码的话,你可以先用username/password来代替,能先给我写一个小demo吗?还有那个root变量表示的是啥? /** * @Description: * * @Title: LdAPTest.java * @Package com.joyce.itext.main * @Copyright: Copyright (c) 2014 * * @author Comsys-LZP * @date 2014-8-7 上午10:20:22 * @version V2.0 */package com.joyce.itext.main;import java.util.Properties;import javax.naming.Context;import javax.naming.NamingEnumeration;import javax.naming.NamingException;import javax.naming.directory.SearchControls;import javax.naming.directory.SearchResult;import javax.naming.ldap.InitialLdapContext;import javax.naming.ldap.LdapContext;/** * @Description:拉取AD域账户 * * @ClassName: LdAPTest * @Copyright: Copyright (c) 2014 * * @author Comsys-LZP * @date 2014-8-7 上午10:20:22 * @version V2.0 */public class LdAPTest { public static void main(String[] args) { Properties env = new Properties(); String adminName = "[email protected]";//username@domain String adminPassword = "admin";//password String ldapURL = "LDAP://10.10.2.153:389";//ip:port env.put(Context.INITIAL_CONTEXT_FACTORY,"com.sun.jndi.ldap.LdapCtxFactory"); env.put(Context.SECURITY_AUTHENTICATION, "simple");//"none","simple","strong" env.put(Context.SECURITY_PRINCIPAL, adminName); env.put(Context.SECURITY_CREDENTIALS, adminPassword); env.put(Context.PROVIDER_URL, ldapURL); try { LdapContext ctx = new InitialLdapContext(env, null); SearchControls searchCtls = new SearchControls(); searchCtls.setSearchScope(SearchControls.SUBTREE_SCOPE); String searchFilter = "(&(objectCategory=person)(objectClass=user)(name=*))"; String searchBase = "DC=2003,DC=com"; String returnedAtts[] = {"memberOf"}; searchCtls.setReturningAttributes(returnedAtts); NamingEnumeration<SearchResult> answer = ctx.search(searchBase, searchFilter,searchCtls); while (answer.hasMoreElements()) { SearchResult sr = (SearchResult) answer.next(); System.out.println("<<<::[" + sr.getName()+"]::>>>>"); } ctx.close(); }catch (NamingException e) { e.printStackTrace(); System.err.println("Problem searching directory: " + e); } }}还是自己来吧! Tomcat启动一段时间后程序不能运行了 求ERWIN 7 软件的下载地址!!!!!!!!!!!!! 数据的同步问题求解 求高手解决删除xml文件中的内容 SSH棘手问题 拜求网络监控的技术指点 全面J2EE书? 请问大家从哪里可以下载到Java源码? jbuilder9的新bug? jbuilder8是否自带j2EE 给一个支持断点续传的j2EE下载地址 有关servlet和框架间各部分通信的问题 SpringMVC Annotation的问题
SearchControls constraints = new SearchControls();
constraints.setSearchScope(SearchControls.SUBTREE_SCOPE);
NamingEnumeration<?> en = dirContext.search(root, "cn=" + usr, constraints);//cn改为你的域名应该就行了。
/**
* @Description:
*
* @Title: LdAPTest.java
* @Package com.joyce.itext.main
* @Copyright: Copyright (c) 2014
*
* @author Comsys-LZP
* @date 2014-8-7 上午10:20:22
* @version V2.0
*/
package com.joyce.itext.main;import java.util.Properties;import javax.naming.Context;
import javax.naming.NamingEnumeration;
import javax.naming.NamingException;
import javax.naming.directory.SearchControls;
import javax.naming.directory.SearchResult;
import javax.naming.ldap.InitialLdapContext;
import javax.naming.ldap.LdapContext;/**
* @Description:拉取AD域账户
*
* @ClassName: LdAPTest
* @Copyright: Copyright (c) 2014
*
* @author Comsys-LZP
* @date 2014-8-7 上午10:20:22
* @version V2.0
*/
public class LdAPTest {
public static void main(String[] args) {
Properties env = new Properties();
String adminName = "[email protected]";//username@domain
String adminPassword = "admin";//password
String ldapURL = "LDAP://10.10.2.153:389";//ip:port
env.put(Context.INITIAL_CONTEXT_FACTORY,"com.sun.jndi.ldap.LdapCtxFactory");
env.put(Context.SECURITY_AUTHENTICATION, "simple");//"none","simple","strong"
env.put(Context.SECURITY_PRINCIPAL, adminName);
env.put(Context.SECURITY_CREDENTIALS, adminPassword);
env.put(Context.PROVIDER_URL, ldapURL);
try {
LdapContext ctx = new InitialLdapContext(env, null);
SearchControls searchCtls = new SearchControls();
searchCtls.setSearchScope(SearchControls.SUBTREE_SCOPE);
String searchFilter = "(&(objectCategory=person)(objectClass=user)(name=*))";
String searchBase = "DC=2003,DC=com";
String returnedAtts[] = {"memberOf"};
searchCtls.setReturningAttributes(returnedAtts);
NamingEnumeration<SearchResult> answer = ctx.search(searchBase, searchFilter,searchCtls);
while (answer.hasMoreElements()) {
SearchResult sr = (SearchResult) answer.next();
System.out.println("<<<::[" + sr.getName()+"]::>>>>");
}
ctx.close();
}catch (NamingException e) {
e.printStackTrace();
System.err.println("Problem searching directory: " + e);
}
}
}还是自己来吧!