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  1.   

      就是我不想让它直接能够访问jsp页面
      

  2.   

    缺少这个?
    <filter>
    <filter-name>springSecurityFilterChain</filter-name>
    <filter-class>org.springframework.web.filter.DelegatingFilterProxy
    </filter-class>
    </filter> <filter-mapping>
    <filter-name>springSecurityFilterChain</filter-name>
    <url-pattern>/*</url-pattern>
    </filter-mapping>
      

  3.   

    不行  加进去报错 下面是我原来的web.xml配置
    <?xml version="1.0" encoding="UTF-8"?>
    <web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns="http://java.sun.com/xml/ns/javaee"
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
    id="WebApp_ID" version="3.0"> <welcome-file-list>
    <welcome-file>index.jsp</welcome-file>
    </welcome-file-list>
    <servlet>
    <servlet-name>Smart2</servlet-name>
    <servlet-class>
    org.springframework.web.servlet.DispatcherServlet
    </servlet-class>
    <init-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>classpath*:/spring/*.xml</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
    </servlet>
    <servlet-mapping>
    <servlet-name>Smart2</servlet-name>
    <url-pattern>/</url-pattern>
    </servlet-mapping>
    <filter>
    <filter-name>CharacterFilter</filter-name>
    <filter-class>
    org.springframework.web.filter.CharacterEncodingFilter
    </filter-class>
    <init-param>
    <param-name>encoding</param-name>
    <param-value>UTF-8</param-value>
    </init-param>
    </filter>
    <filter-mapping>
    <filter-name>CharacterFilter</filter-name>
    <url-pattern>/*</url-pattern>
    </filter-mapping>
    <!-- <error-page>-->
    <!-- <error-code>400</error-code>-->
    <!-- <location>/jsp/error/checkdatabasepage.jsp</location>-->
    <!-- </error-page>-->
    <!-- <error-page>-->
    <!-- <error-code>401</error-code>-->
    <!-- <location>/jsp/error/errorpage.jsp</location>-->
    <!-- </error-page>-->
    <!-- <error-page>-->
    <!-- <error-code>403</error-code>-->
    <!-- <location>/jsp/error/errorpage.jsp</location>-->
    <!-- </error-page>-->
    <!-- <error-page>-->
    <!-- <error-code>404</error-code>-->
    <!-- <location>/jsp/error/errorpage.jsp</location>-->
    <!-- </error-page>-->
    <!-- <error-page>-->
    <!-- <error-code>500</error-code>-->
    <!-- <location>/jsp/error/errorpage.jsp</location>-->
    <!-- </error-page>-->
    </web-app>
      

  4.   

    你 直接地址到jsp好了。不走后台处理。
      

  5.   


    我的意思是:不让地址栏输入jsp路径就能访问
      

  6.   

    把你的jsp页面放到web-inf下面并在spring的配置文件中加上这句话
     <bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver">  
            <property name="prefix" value="/WEB-INF/jsp/" />  
            <property name="suffix" value=".jsp" />  
            <property name="contentType" value="text/html; charset=utf-8"/>
        </bean> 
      

  7.   

      就是我不想让它直接能够访问jsp页面看看这个说明
    http://chinahnzhou.iteye.com/blog/1485379
      

  8.   

    额~~  不能地址栏输入jsp页面就能进入的话,你将所有的jsp页面都放在WEB-INF目录下就好了,这是不能直接用.jsp来访问的    除非用.action跳转之后才能跳转到相应的页面!!  这样应该是可以解决楼主的问题
      

  9.   

    jsp一般都是放在WEB-INF里面,为的就是防止直接访问