为什么我使用了延迟加载过滤器,仍然出现session is closed的异常

Question

本帖最后由 calledMT 于 2010-07-28 10:05:56 编辑

Answer 1

http://cn-done.javaeye.com/blog/579317

Answer 2

<init-param>
<param-name>singleSession</param-name>
<param-value>true</param-value>
</init-param>
带上

Answer 3

Hibernate代码package com.ssh_rooms.dao.imp;import java.util.*;import javax.annotation.Resource;import org.hibernate.HibernateException;
import org.hibernate.Session;
import org.hibernate.SessionFactory;
import org.springframework.stereotype.Repository;
import org.springframework.transaction.annotation.Transactional;import com.ssh_rooms.dao.inf.TenementManager;
import com.ssh_rooms.entity.Tenement;@Transactional
@Repository
public class TenementManagerImp implements TenementManager 
{
@Resource private SessionFactory sessionFactory;
public Tenement login(String name, String password) 
{
return (Tenement)sessionFactory.getCurrentSession().createQuery(hql).setParameter(0, name).setParameter(1, password).uniqueResult(); }
}<------------------分割线----------------------->
Struts代码
package com.ssh_rooms.action;import java.io.*;
import java.net.*;
import java.util.*;import javax.servlet.http.*;import org.apache.struts.action.*;
import org.springframework.stereotype.Controller;import com.ssh_rooms.dao.imp.TenementManagerImp;
import com.ssh_rooms.dao.inf.TenementManager;
import com.ssh_rooms.entity.Tenement;@Controller (value="/login")
public class LoginAction extends Action 
{
private static Properties config = new Properties();
static
  {
    try
    {
      InputStream in = LoginAction.class.getClassLoader().getResourceAsStream("roommanager.properties");
      config.load(in);
      in.close();
    }catch(Exception e)
    {
      e.printStackTrace();
      throw new ExceptionInInitializerError();
    }
  }
public ActionForward execute(ActionMapping mapping, ActionForm form,
HttpServletRequest request, HttpServletResponse response)
throws Exception 
{
LoginForm loginForm=(LoginForm)form;
String username=URLDecoder.decode(loginForm.getUsername(),"utf-8");
System.out.println(username);
String password=loginForm.getPassword();
String rname=config.getProperty("rootname");
String rpwd=config.getProperty("password");
TenementManager tm=new TenementManagerImp();
System.out.println(tm.login("123", "123"));
if(username.equals(rname)&&password.equals(rpwd))
{
return mapping.findForward("success_landlord");
}
else
return mapping.findForward("fail");
}
}

Answer 4

异常信息java.lang.NullPointerException
at com.lw.ssh_rooms.dao.imp.TenementManagerImp.login(TenementManagerImp.java:89)
at com.lw.ssh_rooms.action.LoginAction.execute(LoginAction.java:44)