我想从aa表中读出所有数据,然后在另一个页面显示。 可是我不知道怎么写查询,然后怎么封装到集合。这样写不对:大虾快帮忙吧 我快急死了。
查询方法对吗??
class DAO{
public List sel(){
List ls=new Vector();
Session session = HibernateSessionFactory.openSession();
String hql = "from aa ";
try {
Query query = session.createQuery(hql);
ls = query.list();
return ls;
}
catch(Exception ex){
ex.printStackTrace();
}
return ls;
}action如下:
public ActionForward list(ActionMapping mapping, ActionForm form,
HttpServletRequest request, HttpServletResponse response)throws Exception{
List b=new Vector();
WorkPlan user=new WorkPlan();
DAO a=new DAO();
b=a.sel();
request.setAttribute("all", b);
return mapping.findForward("JSP页面");
}这个不对 大虾帮帮忙 小弟泪流满面提示说找不到配置文件,但是肯定是代码错了 因为我不太会。
查询方法对吗??
class DAO{
public List sel(){
List ls=new Vector();
Session session = HibernateSessionFactory.openSession();
String hql = "from aa ";
try {
Query query = session.createQuery(hql);
ls = query.list();
return ls;
}
catch(Exception ex){
ex.printStackTrace();
}
return ls;
}action如下:
public ActionForward list(ActionMapping mapping, ActionForm form,
HttpServletRequest request, HttpServletResponse response)throws Exception{
List b=new Vector();
WorkPlan user=new WorkPlan();
DAO a=new DAO();
b=a.sel();
request.setAttribute("all", b);
return mapping.findForward("JSP页面");
}这个不对 大虾帮帮忙 小弟泪流满面提示说找不到配置文件,但是肯定是代码错了 因为我不太会。
mapping.findForward("JSP页面");1年没有写web了.总觉得这句话有问题.
JSP页面应该是你需要跳转的页面. 一般应该是mapping.findForward("./result.jsp");
首先是 dao 实现方法
public List getSpreaderNextNum() throws Exception {
return Criteria criteria = this.getSession(true)
.createCriteria(实体类.class).list();
}
action方法:ServletContext application = request.getSession().getServletContext();
WebApplicationContext webContext = WebApplicationContextUtils
.getRequiredWebApplicationContext(application);
SpreaderService sprs = (SpreaderService) webContext.getBean("speaderService");//上面代码是在spring里面配置的service
List res= sprs.getSpreaderNextNum();
return mapping.findForward("***");//*** 应该是你在struts-config.xml 里面配置的跳转路径
eg:<forward name="***" path="/index.jsp"></forward>
要是根据你写的代码。其实问题不大。class DAO{
public List<AA> sel(){
List<AA> ls=new ArrayList<AA>();Session session = HibernateSessionFactory.openSession();
String hql = "from AA";
try {
Query query = session.createQuery(hql);
ls = query.list();
return ls;
}
catch(Exception ex){
ex.printStackTrace();
}
return ls;
}action如下:
public ActionForward list(ActionMapping mapping, ActionForm form,
HttpServletRequest request, HttpServletResponse response)throws Exception{
List<AA> ls=new ArrayList<AA>();
WorkPlan user=new WorkPlan();DAO a=new DAO();
ls=a.sel();
request.setAttribute("all",ls);
return mapping.findForward("showList");}
[code=XML]
<action.........
<forward name="showList" path="/xxxxx.jsp"></forward>
</action>
[/code]
1、在src下有hibernate.cfg.xml的主配置文件
2、建立一个映射文件**.hbm.xml。此文件是你的对象与数据库表的映射文件
3、在主配置文件中,导入了你的映射文件**.hbm.xml
<mapping resource="***.hbm.xml" />
这是jdk5.0后出现的泛型定义..
指list中只能存放<AA>类型的数据.
jsp
<%
for(Object obj:(List)request.getAttribute("all"))
{
dothing.
}
%>