Calendar calendar = Calendar.getInstance(); calendar.setTime(new Date()); ///现在的日期 LZ 可以自定义一个 long timethis = calendar.getTimeInMillis(); calendar.setTime(date); //date为自定义的 long timeend = calendar.getTimeInMillis(); long days = ((timethis - timeend) / (1000 * 60 * 60 * 24))/365; 要获取 相差的 周数 再除以七 试试看...
public static void main(String[] args) { Date date = new Date(); String num = "2009-6-10"; try{ Date m_endTime = new java.text.SimpleDateFormat("yyyy-MM-dd").parse("2009-6-10"); System.out.println((date.getTime()- m_endTime.getTime())/86400000/7); }catch(Exception ex){ ex.printStackTrace(); } }
public static void main(String[] args) { //Date date = new Date(); String strDateStart = "2009-6-10"; String strDateEnd = "2010-6-10"; try{ Date dateStart = new SimpleDateFormat("yyyy-MM-dd").parse(strDateStart ); Date dateEnd = new SimpleDateFormat("yyyy-MM-dd").parse(strDateEnd );
学习了import java.util.*; class gc { public static void main(String[] args) { Date now = new Date(); GregorianCalendar gc = new GregorianCalendar(); gc.set(2010,1,1); Date end = gc.getTime(); long l = now.getTime()-end.getTime(); System.out.println(l/86400000/7); } }
package com.test;import java.text.SimpleDateFormat; import java.util.Date;public class date { public static void main(String[] args) { String start_date = "2009-6-10"; String end_date = "2010-6-10"; int temp = getDays(start_date,end_date); System.out.println(temp); } public static int getDays(String startdate, String enddate) { int temp = 0; try { SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd"); Date dateStart = sdf.parse(startdate); Date dateEnd = sdf.parse(enddate); temp = (int) ((dateEnd.getTime() - dateStart.getTime()) / 86400000 / 7); } catch (Exception ee) { ee.printStackTrace(); } return temp; }} 正确答案。呵呵 O(∩_∩)O~ 谢谢 sxzlc 和 cl61917380
calendar.setTime(new Date()); ///现在的日期 LZ 可以自定义一个
long timethis = calendar.getTimeInMillis();
calendar.setTime(date); //date为自定义的
long timeend = calendar.getTimeInMillis();
long days = ((timethis - timeend) / (1000 * 60 * 60 * 24))/365;
要获取 相差的 周数 再除以七 试试看...
public static void main(String[] args)
{
Date date = new Date();
String num = "2009-6-10";
try{
Date m_endTime = new java.text.SimpleDateFormat("yyyy-MM-dd").parse("2009-6-10");
System.out.println((date.getTime()- m_endTime.getTime())/86400000/7);
}catch(Exception ex){
ex.printStackTrace();
}
}
{
//Date date = new Date();
String strDateStart = "2009-6-10";
String strDateEnd = "2010-6-10";
try{
Date dateStart = new SimpleDateFormat("yyyy-MM-dd").parse(strDateStart );
Date dateEnd = new SimpleDateFormat("yyyy-MM-dd").parse(strDateEnd );
System.out.println((dateEnd .getTime()- dateStart .getTime())/86400000/7);
}catch(Exception ex){
ex.printStackTrace();
}
}
刚才的稍微改了下ctrl + c 之
{
//Date date = new Date();
String strDateStart = "2009-6-10";
String strDateEnd = "2010-6-10"; try{ SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd");
Date dateStart = sdf.parse(strDateStart );
Date dateEnd = sdf.parse(strDateEnd );
System.out.println((dateEnd .getTime()- dateStart .getTime())/86400000/7); }catch(Exception ex){
ex.printStackTrace();
}
}又该了一下!
class gc
{
public static void main(String[] args)
{
Date now = new Date();
GregorianCalendar gc = new GregorianCalendar();
gc.set(2010,1,1);
Date end = gc.getTime();
long l = now.getTime()-end.getTime();
System.out.println(l/86400000/7);
}
}
package com.test;import java.text.SimpleDateFormat;
import java.util.Date;public class date {
public static void main(String[] args) { String start_date = "2009-6-10";
String end_date = "2010-6-10";
int temp = getDays(start_date,end_date);
System.out.println(temp);
} public static int getDays(String startdate, String enddate) {
int temp = 0;
try {
SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd");
Date dateStart = sdf.parse(startdate);
Date dateEnd = sdf.parse(enddate);
temp = (int) ((dateEnd.getTime() - dateStart.getTime()) / 86400000 / 7);
} catch (Exception ee) {
ee.printStackTrace();
}
return temp;
}}
正确答案。呵呵 O(∩_∩)O~ 谢谢 sxzlc 和 cl61917380
因为GregorianCalendar的月是从0开始的