getHibernateTemplate().find()传值问题

Question

getHibernateTemplate().find("from ReplyUser r where r.username=?",new Object[] { userName });
方法里面userName的值始终传不到HQL语句中
然而使用不传递userName的值
getHibernateTemplate().find(from ReplyUser r where r.username=’user‘"）；
却能正常的查找出来库中的数据这是怎么回事啊，该怎么办
下面是DAO的实现类的代码：public ReplyUser getUser(String userName) {
                List users = getHibernateTemplate().find(HQL_GET_USER_BY_USRNAME,
new Object[] { userName });
return (ReplyUser) users.get(0);
}
其中的userName已经被赋值了但是传不进HQL中userName在表中不是主键

Answer 1

个人认为"findByNamedQueryAndNamedParam"比较好用些HQL：
<query name="find.permission.by.level"><![CDATA[
            FROM Permission p
            where p.level = :level
        ]]></query>public List<Permission> finPermissionByPermissionLevel(int level) 
throws ObjectNotFoundException {
return getHibernateTemplate().findByNamedQueryAndNamedParam(
"find.permission.by.level", "level", level); 
}
其中'find.permission.by.level'是映射文件中的HQL名，第一个“level“是变量名，也就是HQL中的":level"，地三个level是需要导入的变量值。

Answer 2

代码中的HQL_GET_USER_BY_USRNAME是
private static final String HQL_GET_USER_BY_USRNAME = "from ReplyUser r where r.username=?";

Answer 3

用
public List<Permission> finPermissionByPermissionLevel(int level) 
        throws ObjectNotFoundException {
        return getHibernateTemplate().findByNamedQueryAndNamedParam(
                "find.permission.by.level", "level", level); 
    }
的话是不是只能传int的值要是我要传别的类型的值该怎么做

Answer 4

什么值都能传！单个数值不用说了，和上面例子中传int是一样的，任何object都可以，getHibernateTemplate().findByNamedQueryAndNamedParam 返回的是一个List<Object>。
如果是多个数值可以这样：
public List<Permission> findPermissionByDateAndLevel(Date date, int level) {

return getHibernateTemplate().
findByNamedQueryAndNamedParam("find.permission.by.date.and.level", 
new String[] {"theDate", "permissionLevel"}, 
new Object[] {date, new Integer(level)} ); 
}
根据这个例子可以看出，可以传入的数值甚至不用是同一数据类型。在这个例子中，HQL当然应该要求两个数值的输入，其中的变量分别命名为 ":theDate", ":permissionLevel"

Answer 5

谁知道为什么传值传不到HQL中，findPermissionByDateAndLevel也是同样的问题也传不进去

Answer 6

如果还是传不进去，那可能就是你的Hibernate设置有问题。如果可以的话把映射文件发上来看看。如果用Spring的话最好把applicationContext.xml也发上来看看。

Answer 7

映射文件是通过自动生成的，应该不能够改什么了吧applicationContext.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:aop="http://www.springframework.org/schema/aop"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-2.0.xsd
http://www.springframework.org/schema/aop
http://www.springframework.org/schema/aop/spring-aop-2.0.xsd
http://www.springframework.org/schema/tx
http://www.springframework.org/schema/tx/spring-tx-2.0.xsd"> <bean id="dataSource"
class="org.apache.commons.dbcp.BasicDataSource">
<property name="driverClassName">
<value>oracle.jdbc.driver.OracleDriver</value>
</property>
<property name="url">
<value>jdbc:oracle:thin:@neusoft:1521:MYORCL</value>
</property>
<property name="username">
<value>reply</value>
</property>
<property name="password">
<value>123456</value>
</property>
</bean> <!-- 配置SessionFactory -->
<bean id="sessionFactory"
class="org.springframework.orm.hibernate3.LocalSessionFactoryBean">
<property name="dataSource">
<ref bean="dataSource" />
</property>
<!-- 配置Hibernate的属性 -->
<property name="hibernateProperties">
<props>
<prop key="hibernate.dialect">
org.hibernate.dialect.Oracle9Dialect
</prop>
<prop key="hibernate.show_sql">true</prop>
</props>
</property>
<!-- 指定HIbernate映射文件的路径 -->
<property name="mappingResources">
<list>
<value>/org/neo/reply/model/ReplyUser.hbm.xml</value>
<value>/org/neo/reply/model/ReplyTeacher.hbm.xml</value>
<value>/org/neo/reply/model/ReplyStudent.hbm.xml</value>
<value>/org/neo/reply/model/ReplyLession.hbm.xml</value>
<value>
/org/neo/reply/model/ReplyDepartment.hbm.xml
</value>
<value>/org/neo/reply/model/ReplyClass.hbm.xml</value>
<value>/org/neo/reply/model/ReplyAdmin.hbm.xml</value>
</list>
</property>
</bean> <!-- USERDAO -->
<bean id="replyUserDao"
class="org.neo.reply.dao.hibernate.ReplyUserDaoHibernate">
<property name="sessionFactory">
<ref bean="sessionFactory" />
</property>
</bean> <bean id="replyUserManager"
class="org.neo.reply.service.impl.ReplyUserManagerImpl">
<property name="replyUserDao">
<ref bean="replyUserDao" />
</property>
</bean> <!-- TEACHERDAO -->
<bean id="teacherDao"
class="org.neo.reply.dao.hibernate.TeacherDaoHibernate">
<property name="sessionFactory">
<ref bean="sessionFactory" />
</property>
</bean> <!-- STUDENTDAO -->
<bean id="studentDao"
class="org.neo.reply.dao.hibernate.StudentDaoHibernate">
<property name="sessionFactory">
<ref bean="sessionFactory" />
</property>
</bean>
<bean id="studentManager"
class="org.neo.reply.service.impl.StudnetManagerImpl">
<property name="studentDao">
<ref bean="studentDao" />
</property>
</bean> <!-- UserBean  -->
<bean id="loginViewBean"
class="org.neo.reply.action.ReplyUserAction" scope="prototype">
<property name="replyUserManager">
<ref bean="replyUserManager" />
</property>
</bean> <bean id="getUser" class="org.neo.reply.action.ReplyUserAction"
scope="prototype">
<property name="replyUserManager">
<ref bean="replyUserManager" />
</property>
</bean> <!-- STUDENTBEAN -->
<bean id="getStudent" class="org.neo.reply.action.StudentAction"
scope="prototype">
<property name="studentManager">
<ref bean="studentManager" />
</property>
</bean>
<bean id="transactionManager"
class="org.springframework.orm.hibernate3.HibernateTransactionManager">
<property name="sessionFactory">
<ref local="sessionFactory" />
</property>
</bean> <!-- 配置事务特性，配置add,delete和update开始的方法， 事务传播特性为required-->
<tx:advice id="txAdvice" transaction-manager="transactionManager">
<tx:attributes>
<tx:method name="get*" propagation="REQUIRED" />
<tx:method name="add*" propagation="REQUIRED" />
<tx:method name="delete*" propagation="REQUIRED" />
<tx:method name="update*" propagation="REQUIRED" />
<tx:method name="*" read-only="true" />
</tx:attributes>
</tx:advice> <!-- 配置那些类的方法进行事务管理，当前org.neo.reply.service包中的子包，类中所有方法需要，还需要参考tx:advice的配置 -->
<aop:config>
<aop:pointcut id="allManagerMethod"
expression="execution(* org.neo.reply.service.*.*(..))" />
<aop:advisor advice-ref="txAdvice"
pointcut-ref="allManagerMethod" />
</aop:config>
</beans>
struts.xml<?xml version="1.0" encoding="UTF-8" ?>
<!DOCTYPE struts PUBLIC
    "-//Apache Software Foundation//DTD Struts Configuration 2.0//EN"
    "http://struts.apache.org/dtds/struts-2.0.dtd"><struts>
<!-- 将action托管给spring -->
<constant name="struts.objectFactory" value="spring" />
<package name="reply-default" extends="struts-default"> <action name="login_view" class="loginViewBean"
method="loginView">
<result type="redirect">login_view.jsp</result>
</action> <action name="login" class="getUser" method="login">
<result name="admin">admin/list_admin.jsp</result>
<result name="teacher">teacher/list_teacher.jsp</result>
<result name="student">student.action</result>
<result name="register">register.jsp</result>
</action>
</package>
<include file="struts/reply-admin.xml" />
<include file="struts/reply-teacher.xml" />
<include file="struts/reply-student.xml" /></struts>

Answer 8

我创建的是多表连接的产生了很多标的配置属性
标的配置没有改变过REPLY_USER表的配置文件
<?xml version="1.0" encoding="utf-8"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<!-- 
    Mapping file autogenerated by MyEclipse Persistence Tools
-->
<hibernate-mapping>
    <class name="org.neo.reply.model.ReplyUser" table="REPLY_USER" schema="REPLY">
        <id name="userid" type="java.lang.Long">
            <column name="USERID" precision="6" scale="0" />
            <generator class="increment"></generator>
        </id>
        <property name="username" type="java.lang.String">
            <column name="USERNAME" length="20" not-null="true" unique="true" />
        </property>
        <property name="userpassword" type="java.lang.String">
            <column name="USERPASSWORD" length="20" not-null="true" />
        </property>
        <property name="competence" type="java.lang.Long">
            <column name="COMPETENCE" precision="1" scale="0" not-null="true" />
        </property>
        <set name="replyTeachers" inverse="true">
            <key>
                <column name="USERID" precision="6" scale="0" />
            </key>
            <one-to-many class="org.neo.reply.model.ReplyTeacher" />
        </set>
        <set name="replyStudents" inverse="true">
            <key>
                <column name="USERID" precision="6" scale="0" />
            </key>
            <one-to-many class="org.neo.reply.model.ReplyStudent" />
        </set>
        <set name="replyAdmins" inverse="true">
            <key>
                <column name="USERID" precision="6" scale="0" />
            </key>
            <one-to-many class="org.neo.reply.model.ReplyAdmin" />
        </set>
    </class>
</hibernate-mapping>配置文件生成的代码
package org.neo.reply.model;import java.util.HashSet;
import java.util.Set;/**
 * ReplyUser entity.
 * 
 * @author MyEclipse Persistence Tools
 */public class ReplyUser implements java.io.Serializable { // Fields /**
 * 
 */
private static final long serialVersionUID = 6658430530569766240L;
private Long userid;
private String username;
private String userpassword;
private Long competence;
private Set replyTeachers = new HashSet(0);
private Set replyStudents = new HashSet(0);
private Set replyAdmins = new HashSet(0); // Constructors /** default constructor */
public ReplyUser() {
} /** minimal constructor */
public ReplyUser(String username, String userpassword, Long competence) {
this.username = username;
this.userpassword = userpassword;
this.competence = competence;
} /** full constructor */
public ReplyUser(String username, String userpassword, Long competence,
Set replyTeachers, Set replyStudents, Set replyAdmins) {
this.username = username;
this.userpassword = userpassword;
this.competence = competence;
this.replyTeachers = replyTeachers;
this.replyStudents = replyStudents;
this.replyAdmins = replyAdmins;
} // Property accessors public Long getUserid() {
return this.userid;
} public void setUserid(Long userid) {
this.userid = userid;
} public String getUsername() {
return this.username;
} public void setUsername(String username) {
this.username = username;
} public String getUserpassword() {
return this.userpassword;
} public void setUserpassword(String userpassword) {
this.userpassword = userpassword;
} public Long getCompetence() {
return this.competence;
} public void setCompetence(Long competence) {
this.competence = competence;
} public Set getReplyTeachers() {
return this.replyTeachers;
} public void setReplyTeachers(Set replyTeachers) {
this.replyTeachers = replyTeachers;
} public Set getReplyStudents() {
return this.replyStudents;
} public void setReplyStudents(Set replyStudents) {
this.replyStudents = replyStudents;
} public Set getReplyAdmins() {
return this.replyAdmins;
} public void setReplyAdmins(Set replyAdmins) {
this.replyAdmins = replyAdmins;
}

Answer 9

这是我建表的语句
/数据库新建用户，用户通过normal的型式登录/
create user reply identified by "123456"
default tablespace users quota 10M on users account lock;grant create session,create table,create view to reply;
/开始建的表/
create table REPLY_USER(
USERID number(6) constraint s_pk primary key,
USERNAME char(20) not null,
USERPASSWORD char(20) not null,
COMPETENCE number(1) not null
)alter table reply_user add constraint P_UK unique(username)create sequence SEQ_REPLY_USER; insert into REPLY_USER values(seq_REPLY_USER.nextval,'admin1',111,1);
create table REPLY_ADMIN(
USERID number(6) references reply_user(USERID),
ADMINNAME char(20) not null
)CREATE TABLE REPLY_TEACHER(
USERID number(6) references reply_user(USERID),
TEACHERNAME CHAR(20) NOT NULL,
TEACHERSEX CHAR(2),
TEACHERBIRTHDAY DATE,
TEACHERWORKDAY DATE,
TEACHERDEPARTMENTID number(6) primary key   //系别号
);CREATE TABLE REPLY_DEPARTMENT(
DEPARTMENTID number(6) references REPLY_TEACHER(TEACHERDEPARTMENTID),//系别号
DEPARTMENTNAME CHAR(20) UNIQUE    //系名                   
)CREATE TABLE REPLY_STUDENT(
USERID number(6) references reply_user(USERID),
STUDENTNUMBER number(6) primary key,
NAME CHAR(20) NOT NULL,
SEX CHAR(2),
BIRTHDAY DATE,
STUDENTDAY DATE,
CLASSID NUMBER(6) ,
REPLAYNUMBER NUMBER(6),
TEACHERCOMMENT char,               //教师评语
TEACHERID number(6)                //教师用户名ID
)CREATE TABLE REPLY_CLASS(
CLASSID NUMBER(6),                  //班级ID
CLASSNAME CHAR(20) unique,          //班级名称
DEPARTMENTID NUMBER(6) NOT NULL       //系别号
)CREATE TABLE REPLY_LESSION(
LESSIONID number(6) primary key,
LESSIONNAME CHAR(20) unique                 
)CREATE TABLE REPLY_RESULT(
STUDENTNUMBER number(6) REFERENCES REPLY_STUDENT(STUDENTNUMBER),
LESSIONID number(6) REFERENCES REPLY_LESSION(LESSIONID),
RESULTNUMBER NUMBER(6)
)

Answer 10

getHibernateTemplate().find("from ReplyUser r where r.username=?", userName );

Answer 11

getHibernateTemplate().find("from ReplyUser r where r.username=?", userName );
也没用还是同样的问题

Answer 12

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee 
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"> <!-- spring params -->
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/applicationContext*.xml</param-value>
</context-param> <!-- spring的监听器，以便在启动时就自动加载spring的配置 -->
<listener>
<listener-class>
org.springframework.web.context.ContextLoaderListener
</listener-class>
</listener>

<!-- OpenSessionInViewFilter过滤器 -->
<filter>
<filter-name>lazyLoadingFilter</filter-name>
<filter-class>
org.springframework.orm.hibernate3.support.OpenSessionInViewFilter
</filter-class>
</filter> <!-- struts2 过滤器 -->
<filter>
<filter-name>struts2</filter-name>
<filter-class>
org.apache.struts2.dispatcher.FilterDispatcher
</filter-class>
</filter> <filter-mapping>
<filter-name>lazyLoadingFilter</filter-name>
<url-pattern>*.action</url-pattern>
</filter-mapping> <filter-mapping>
<filter-name>struts2</filter-name>
<url-pattern>*.action</url-pattern>
</filter-mapping> <welcome-file-list>
<welcome-file>index.jsp</welcome-file>
<welcome-file>index.html</welcome-file>
</welcome-file-list>
</web-app>