HTTP Status 404错误求助

Question

web.xml代码
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" 
xmlns="http://java.sun.com/xml/ns/javaee" 
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee 
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">

<servlet>
<servlet-name>login</servlet-name>
<servlet-class>com.chinantn.test.LoginAction</servlet-class>
</servlet>

<servlet-mapping>
<servlet-name>login</servlet-name>
<url-pattern>/login</url-pattern>
</servlet-mapping>

  <welcome-file-list>
    <welcome-file>/jsp/test/login.jsp</welcome-file>
  </welcome-file-list>
</web-app>
怎么该都出不来真确的，哪位高手知道怎么回事啊？

Answer 1

<welcome-file-list>
  <welcome-file>/jsp/test/login.jsp</welcome-file>
  </welcome-file-list>
这样不就能找到了么？

Answer 2

HTTP Status 404 - /serveltLX/--------------------------------------------------------------------------------type Status reportmessage /serveltLX/description The requested resource (/serveltLX/) is not available.
错误提示

Answer 3

<welcome-file-list>
  <welcome-file>jsp/test/login.jsp</welcome-file><!--要保证路径正确-->
</welcome-file-list>