java怎么获取远程带参数的xml文件？

Question

java怎么获取远程带参数的xml文件？
类似地址：
http://192.168.1.100/test.jsp?cindex=2&pagesize=2如果没有带有参数的地址：像
http://192.168.1.100/test.xml就能获取。 

Answer 1

String url = "http://board2.finance.daum.net/gaia/do/xml/finance/read?bbsId=stock&articleId=1673473&pageIndex=1&viewObj=1:2:0"; 
URLConnection uc = new URL(url).openConnection(); 
uc.setConnectTimeout(10000); 
uc.setDoOutput(true); 
InputStream in = new BufferedInputStream(uc.getInputStream()); 
Reader rd = new InputStreamReader(in,"UTF-8"); 
int c = 0; 
while ((c = rd.read()) != -1) { 
temp.append((char) c); 
} 
in.close(); 
strHtml = temp.toString(); 
strHtml 就是读取过来的xml

Answer 2

package com.commons;import java.io.IOException;
import java.io.InputStream;
import java.net.HttpURLConnection;
import java.net.MalformedURLException;
import java.net.URL;
import java.net.URLConnection;import javax.xml.parsers.*;
import org.w3c.dom.Document;public class XmlClass { //解析一个来自所请求的URL的XML文档
 public static Document getDocument(String urlString) {
    try {
      URL url = new URL( urlString );
      try {
        URLConnection URLconnection =url.openConnection ( ) ;
        HttpURLConnection httpConnection =(HttpURLConnection)URLconnection;
        int responseCode =httpConnection.getResponseCode ( ) ;
        if ( responseCode == HttpURLConnection.HTTP_OK) {
            InputStream in = httpConnection.getInputStream ( ) ;
            try {
             DocumentBuilderFactory factory=DocumentBuilderFactory.newInstance();
                DocumentBuilder db=factory.newDocumentBuilder();
             Document doc = db.parse(in);
                return doc;
            } catch(Exception e ) {
                 e.printStackTrace ( ) ;
            }
         } else {
             System.out.println( "HTTP connection response !=HTTP_OK" );
         }
      } catch(IOException e) {
           e.printStackTrace ( ) ;
      }
   } catch (MalformedURLException e ) { 
       e.printStackTrace ( ) ;
   }
   return null;
 }}

Answer 3

import java.io.BufferedInputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.Reader;
import java.io.UnsupportedEncodingException;
import java.net.MalformedURLException;
import java.net.URL;
import java.net.URLConnection;public class roXML {
    public static void main(String[] args) {
     try {
String url = "http://board2.finance.daum.net/gaia/do/xml/finance/read?bbsId=stock&articleId=1673473&pageIndex=1&viewObj=1:2:0"; 
URLConnection uc = new URL(url).openConnection(); 
uc.setConnectTimeout(10000); 
uc.setDoOutput(true); 
InputStream in = new BufferedInputStream(uc.getInputStream()); 
Reader rd = new InputStreamReader(in,"UTF-8");
StringBuffer temp = new StringBuffer();
String strHtml = null;
int c = 0; 
while ((c = rd.read()) != -1) { 
temp.append((char) c); 
} 
in.close(); 
strHtml = temp.toString();
} catch (MalformedURLException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (UnsupportedEncodingException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} 
    }
}====================
at java.net.SocketInputStream.read(Unknown Source)
at java.io.BufferedInputStream.fill(Unknown Source)
at java.io.BufferedInputStream.read1(Unknown Source)
at java.io.BufferedInputStream.read(Unknown Source)
at sun.net.www.http.HttpClient.parseHTTPHeader(Unknown Source)
at sun.net.www.http.HttpClient.parseHTTP(Unknown Source)
at sun.net.www.http.HttpClient.parseHTTP(Unknown Source)
at sun.net.www.protocol.http.HttpURLConnection.getInputStream(Unknown Source)
at com.xml.roXML.main(roXML.java:20)

Answer 4

java.net.SocketException: Connection reset
at java.net.SocketInputStream.read(Unknown Source)
at java.io.BufferedInputStream.fill(Unknown Source)
at java.io.BufferedInputStream.read1(Unknown Source)
at java.io.BufferedInputStream.read(Unknown Source)
at sun.net.www.http.HttpClient.parseHTTPHeader(Unknown Source)
at sun.net.www.http.HttpClient.parseHTTP(Unknown Source)
at sun.net.www.http.HttpClient.parseHTTP(Unknown Source)
at sun.net.www.protocol.http.HttpURLConnection.getInputStream(Unknown Source)