java怎么取每次取json的10条数据，不能重复的那种，各位大佬，麻烦指点一下

Question

{
"rows": [{
"dmjb": "S",
"xgsj": "201805152141",
"ap": ""
}, {
"dmjb": "S",
"xgsj": "201805152141",
"ap": ""
}, {
"dmjb": "S",
"xgsj": "201805152141",
"ap": ""
}, {
"dmjb": "S",
"xgsj": "201805152141",
"ap": ""
}, {
"dmjb": "S",
"xgsj": "201805152141",
"ap": ""
}, {
"dmjb": "S",
"xgsj": "201805152141",
"ap": ""
}, {

"dmjb": "S",
"xgsj": "201805152141",
"ap": ""
}, {

"dmjb": "S",
"xgsj": "201805152141",
"ap": ""
}, {
"dmjb": "S",
"xgsj": "201805152141",
"ap": ""
}, {
"dmjb": "S",
"xgsj": "201805152141",
"ap": ""
}, {
"dmjb": "S",
"xgsj": "201805152141",
"ap": ""
}, {
"dmjb": "S",
"xgsj": "201805152141",
"ap": ""
}, {
"dmjb": "S",
"xgsj": "201805152141",
"ap": ""
}, {
"dmjb": "S",
"xgsj": "201805152141",
"ap": ""
}, {
"dmjb": "G",
"xgsj": "201805281508",
"ap": "0"
}, {
"dmjb": "S",
"xgsj": "201805152141",
"ap": ""
}, {
"dmjb": "S",
"xgsj": "201805152141",
"ap": ""
}, {
"dmjb": "S",
"xgsj": "201805152141",
"ap": ""
}, {
"dmjb": "S",
"xgsj": "201805152141",
"ap": ""
}, {
"dmjb": "S",
"xgsj": "201805152141",
"ap": ""
}, {
"dmjb": "S",
"xgsj": "201805152141",
"ap": ""
}, {
"dmjb": "S",
"xgsj": "201805152141",
"ap": ""
}, {
"dmjb": "S",
"xgsj": "201805152141",
"ap": ""
}, {
"dmjb": "S",
"xgsj": "201805152141",
"ap": ""
}]
}
这是json的一部分，我每次要去里面的10条，不能重复的那种，各位大佬，麻烦指点一下

Answer 1

json字符串转成对象集合，遍历的时候添加一个标记位不就好了

Answer 2

我觉得你应该把原始需求说出来,感觉你说的东西是你的做的东西里的方案一部分,但感觉到一股不合理的解决方案的气息如果你真想这么做,建议先将json转成java集合(fastjson,gson),然后去重,然后再依次取10条,如果你先取再去重,那第一批和第二批就可能存在重复,但同一批次没有重复,这个可能存在bug

Answer 3

json解析放到数据库中，查询时添加去重条件每次取10条

Answer 4

json转对象啊！然后遍历对象，每次传要取的下标范围，就可以读取了啊！

Answer 5

需引用fastjson包地址如下
http://central.maven.org/maven2/com/alibaba/fastjson/1.2.58/fastjson-1.2.58.jar
功能实现代码如下
//JSON数据
String str = "{\"rows\":[{\"dmjb\":\"S\",\"xgsj\":\"201805152141\",\"ap\":\"\"},{\"dmjb\":\"S\",\"xgsj\":\"201805152141\",\"ap\":\"\"},{\"dmjb\":\"S\",\"xgsj\":\"201805152141\",\"ap\":\"\"},{\"dmjb\":\"S\",\"xgsj\":\"201805152141\",\"ap\":\"\"},{\"dmjb\":\"S\",\"xgsj\":\"201805152141\",\"ap\":\"\"},{\"dmjb\":\"S\",\"xgsj\":\"201805152141\",\"ap\":\"\"},{\"dmjb\":\"S\",\"xgsj\":\"201805152141\",\"ap\":\"\"},{\"dmjb\":\"S\",\"xgsj\":\"201805152141\",\"ap\":\"\"},{\"dmjb\":\"S\",\"xgsj\":\"201805152141\",\"ap\":\"\"},{\"dmjb\":\"S\",\"xgsj\":\"201805152141\",\"ap\":\"\"},{\"dmjb\":\"S\",\"xgsj\":\"201805152141\",\"ap\":\"\"},{\"dmjb\":\"S\",\"xgsj\":\"201805152141\",\"ap\":\"\"},{\"dmjb\":\"S\",\"xgsj\":\"201805152141\",\"ap\":\"\"},{\"dmjb\":\"S\",\"xgsj\":\"201805152141\",\"ap\":\"\"},{\"dmjb\":\"G\",\"xgsj\":\"201805281508\",\"ap\":\"0\"},{\"dmjb\":\"S\",\"xgsj\":\"201805152141\",\"ap\":\"\"},{\"dmjb\":\"S\",\"xgsj\":\"201805152141\",\"ap\":\"\"},{\"dmjb\":\"S\",\"xgsj\":\"201805152141\",\"ap\":\"\"},{\"dmjb\":\"S\",\"xgsj\":\"201805152141\",\"ap\":\"\"},{\"dmjb\":\"S\",\"xgsj\":\"201805152141\",\"ap\":\"\"},{\"dmjb\":\"S\",\"xgsj\":\"201805152141\",\"ap\":\"\"},{\"dmjb\":\"S\",\"xgsj\":\"201805152141\",\"ap\":\"\"},{\"dmjb\":\"S\",\"xgsj\":\"201805152141\",\"ap\":\"\"},{\"dmjb\":\"S\",\"xgsj\":\"201805152141\",\"ap\":\"\"}]}";
//将JSON数据转换对象
JSONObject parseObject = JSON.parseObject(str);
//获取JSON对象中的数据行
String rows = parseObject.get("rows").toString();
//转换JSON数据行为List对象
List<Map> rowsMap = JSON.parseArray(rows,Map.class);

//每页条数
int pageSize = 10; 
//总页数
int pageCount = rowsMap.size()/pageSize+(rowsMap.size()%pageSize > 0?1:0); 

//每次取一页  一页10条
for (int currentPage = 1 ; currentPage < pageCount ; currentPage++) {

System.out.println("页数："+currentPage);
for (int i = (currentPage-1)*pageSize; i < currentPage*pageSize; i++)  {
System.out.print("第："+(i+1));
System.out.println("条  数据："+rowsMap.get(i).toString());
}
}

Answer 6

把json转成list，循环出来

Answer 7

你把他转换成jsonARRAY

Answer 8

用甲骨文自带的JSONARRAY就行