public class TestArgs1 {
public static void main(String[] args) throws NumberFormatException {
if(args.length < 3){
System.out.println("Usage: \"param1\" \"param2\" \"param3\"");
System.exit(-1);
}
else{
double d1 = Double.parseDouble(args[0]);
double d2 = Double.parseDouble(args[2]);
if(args[1].equals("*")) System.out.println(d1 * d2);//此处的"*"倘若改成其它的如"x"便可通过 else {
System.out.println("Error: please try again!");
}
}
}
}报Exception啊,怎么回事,和"*"有关系吗?
public static void main(String[] args) throws NumberFormatException {
if(args.length < 3){
System.out.println("Usage: \"param1\" \"param2\" \"param3\"");
System.exit(-1);
}
else{
double d1 = Double.parseDouble(args[0]);
double d2 = Double.parseDouble(args[2]);
if(args[1].equals("*")) System.out.println(d1 * d2);//此处的"*"倘若改成其它的如"x"便可通过 else {
System.out.println("Error: please try again!");
}
}
}
}报Exception啊,怎么回事,和"*"有关系吗?
是这样给 args 赋值的
Run->Open Run Dialog->Arguments->Program arguments那么 *好就回有问题