刚学的struts,总是出现404的错误,搞了几个小时都没有找到错误,我看的是王勇的struts视频,刚开始以为是配置文件写错了,但是我把原版的配置文件拷贝过来,还是这个错误啊!struts-config.xml<?xml version="1.0" encoding="ISO-8859-1" ?><!DOCTYPE struts-config PUBLIC
"-//Apache Software Foundation//DTD Struts Configuration 1.3//EN"
"http://struts.apache.org/dtds/struts-config_1_3.dtd"><struts-config>
<form-beans>
<form-bean name="calForm" type="struts.CalActionForm"></form-bean>
</form-beans><action-mappings>
<action path="/cal"
type="struts.CalAction"
name="calForm"
scope="request"
>
<forward name="success" path="/success.jsp" />
<forward name="error" path="/error.jsp" />
</action>
</action-mappings>
</struts-config>web.xml
<?xml version="1.0" encoding="ISO-8859-1"?> <!DOCTYPE web-app PUBLIC
"-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
"http://java.sun.com/dtd/web-app_2_3.dtd"><web-app>
<display-name>Struts Blank Application</display-name>
<!-- Standard Action Servlet Configuration -->
<servlet>
<servlet-name>action</servlet-name>
<servlet-class>org.apache.struts.action.ActionServlet</servlet-class>
<init-param>
<param-name>config</param-name>
<param-value>/WEB-INF/struts-config.xml</param-value>
</init-param>
<load-on-startup>2</load-on-startup>
</servlet>
<!-- Standard Action Servlet Mapping -->
<servlet-mapping>
<servlet-name>action</servlet-name>
<url-pattern>*.do</url-pattern>
</servlet-mapping>
<!-- The Usual Welcome File List -->
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
"-//Apache Software Foundation//DTD Struts Configuration 1.3//EN"
"http://struts.apache.org/dtds/struts-config_1_3.dtd"><struts-config>
<form-beans>
<form-bean name="calForm" type="struts.CalActionForm"></form-bean>
</form-beans><action-mappings>
<action path="/cal"
type="struts.CalAction"
name="calForm"
scope="request"
>
<forward name="success" path="/success.jsp" />
<forward name="error" path="/error.jsp" />
</action>
</action-mappings>
</struts-config>web.xml
<?xml version="1.0" encoding="ISO-8859-1"?> <!DOCTYPE web-app PUBLIC
"-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
"http://java.sun.com/dtd/web-app_2_3.dtd"><web-app>
<display-name>Struts Blank Application</display-name>
<!-- Standard Action Servlet Configuration -->
<servlet>
<servlet-name>action</servlet-name>
<servlet-class>org.apache.struts.action.ActionServlet</servlet-class>
<init-param>
<param-name>config</param-name>
<param-value>/WEB-INF/struts-config.xml</param-value>
</init-param>
<load-on-startup>2</load-on-startup>
</servlet>
<!-- Standard Action Servlet Mapping -->
<servlet-mapping>
<servlet-name>action</servlet-name>
<url-pattern>*.do</url-pattern>
</servlet-mapping>
<!-- The Usual Welcome File List -->
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
解决方案 »
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检查是这个路径么?
改为
encoding="UTF-8"检查action 里面是不是:
return mapping.findForward("success");
和
return mapping.findForward("error");另外你的页面action写对没?是不是按配置里面方的文件?
http://www.blogjava.net/max/archive/2006/10/10/74353.html
type="struts.CalAction"
name="calForm"
scope="request"
>
估计是这段配置与前面的CalAction类不协调
你的CalAction类是继承MappingDispatchAction 还是继承Action
若是前者那这段配置是<action path="/cal"
parameter="你在CalAction类中的方法名"
type="struts.CalAction"
name="calForm"
scope="request"
>
若是后者,即继承Action
配置是<action path="/CalAction" type="struts.CalAction"
name="calForm"
scope="request"
>