最近学习struts2的框架,在配置spring的时候,出了一个问题。
我的web.xml
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/classes/applicationContext.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>applicationContext.xml我是放在/WEB-INF/classes/下面,内容是:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:jee="http://www.springframework.org/schema/jee"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.0.xsd
http://www.springframework.org/schema/jee http://www.springframework.org/schema/jee/spring-jee-2.0.xsd"> <bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close">
<property name="driverClassName" value="oracle.jdbc.driver.OracleDriver"/>
<property name="url" value="略"/>
<property name="username" value="略"/>
<property name="password" value="略"/>
</bean>
</beans>但是在启动tomcat的时候,发生了错误,日志如下:
2009-08-04 16:07:24,281-[TS] ERROR main org.springframework.web.context.ContextLoader - Context initialization failed
org.springframework.beans.factory.BeanDefinitionStoreException: Unexpected exception parsing XML document from ServletContext resource [/WEB-INF/classes/applicationContext.xml]; nested exception is java.lang.IllegalArgumentException: Class [org.apache.xbean.spring.context.v2.XBeanNamespaceHandler] does not implement the NamespaceHandler interface
Caused by:
java.lang.IllegalArgumentException: Class [org.apache.xbean.spring.context.v2.XBeanNamespaceHandler] does not implement the NamespaceHandler interface
at org.springframework.beans.factory.xml.DefaultNamespaceHandlerResolver.initHandlerMappings(DefaultNamespaceHandlerResolver.java:119)
略网上搜索了很久,也没找到如何解决问题,望有经验高手不吝赐教
我的web.xml
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/classes/applicationContext.xml</param-value>
</context-param>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>applicationContext.xml我是放在/WEB-INF/classes/下面,内容是:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:jee="http://www.springframework.org/schema/jee"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.0.xsd
http://www.springframework.org/schema/jee http://www.springframework.org/schema/jee/spring-jee-2.0.xsd"> <bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close">
<property name="driverClassName" value="oracle.jdbc.driver.OracleDriver"/>
<property name="url" value="略"/>
<property name="username" value="略"/>
<property name="password" value="略"/>
</bean>
</beans>但是在启动tomcat的时候,发生了错误,日志如下:
2009-08-04 16:07:24,281-[TS] ERROR main org.springframework.web.context.ContextLoader - Context initialization failed
org.springframework.beans.factory.BeanDefinitionStoreException: Unexpected exception parsing XML document from ServletContext resource [/WEB-INF/classes/applicationContext.xml]; nested exception is java.lang.IllegalArgumentException: Class [org.apache.xbean.spring.context.v2.XBeanNamespaceHandler] does not implement the NamespaceHandler interface
Caused by:
java.lang.IllegalArgumentException: Class [org.apache.xbean.spring.context.v2.XBeanNamespaceHandler] does not implement the NamespaceHandler interface
at org.springframework.beans.factory.xml.DefaultNamespaceHandlerResolver.initHandlerMappings(DefaultNamespaceHandlerResolver.java:119)
略网上搜索了很久,也没找到如何解决问题,望有经验高手不吝赐教
<beans default-lazy-init="false" default-dependency-check="none" default-autowire="no">
<bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close">
<property name="driverClassName" value="com.mysql.jdbc.Driver"/>
<property name="url" value="jdbc:mysql://IPAddress:3306/databaseName?useUnicode=true&characterEncoding=UTF8&autoGenerateTestcaseScript=true&elideSetAutoCommits=true&prepStmtCacheSize=100&prepStmtCacheSqlLimit=512&maintainTimeStats=false&cacheCallableStmts=true&dontTrackOpenResources=true&useLocalSessionState=true"/>
<property name="username" value="test"/>
<property name="password" value="111111"/>
<property name="maxActive" value="10"/>
<property name="initialSize" value="5"/>
</bean>
<bean id="service" class="com.igobb.service.Service" autowire="byName"/>
</beans>web.xml的配置文件:
<?xml version="1.0" encoding="UTF-8"?>
<web-app id="WebApp_ID" version="2.4"
xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
<!--<session-config>
<session-timeout>20</session-timeout>
</session-config>--> <context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring.xml</param-value>
</context-param> <servlet>
<servlet-name>context</servlet-name>
<servlet-class>
org.springframework.web.context.ContextLoaderServlet
</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<!--<servlet>
<servlet-name>initServlet</servlet-name>
<servlet-class>com.project.system.InitServlet</servlet-class>
<load-on-startup>3</load-on-startup>
</servlet>-->
<servlet>
<servlet-name>projectName</servlet-name>
<servlet-class>
org.springframework.web.servlet.DispatcherServlet
</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>projectName</servlet-name>
<url-pattern>*.htm</url-pattern>
</servlet-mapping>
<welcome-file-list>
<welcome-file>index.htm</welcome-file>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
<!-- application manager start-->
<!--<servlet>
<servlet-name>applicationManager</servlet-name>
<servlet-class>com.igobb.system.ApplicationManager</servlet-class>
<load-on-startup>3</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>applicationManager</servlet-name>
<url-pattern>
/applicationManager
</url-pattern>
</servlet-mapping>-->
<!-- application manager end-->
</web-app>
另外struts还有一个自己的配置文件:
projectName-servlet.xml:
<beans>
<bean id="babymeController" class="com.project.web.AController">
<property name="methodNameResolver">
<ref bean="methodNameResolver"/>
</property>
</bean>
<bean id="urlMapping"
class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping">
<property name="mappings">
<props>
<prop key="/member/*.htm">memberController</prop>
....
</props>
</property>
</bean>
<bean id="methodNameResolver" class="org.springframework.web.servlet.mvc.multiaction.ParameterMethodNameResolver">
<property name="paramName" value="m"/>//这里是你的url路径 例如:/product/a.htm?m=myMethodName&a=1
<property name="defaultMethodName" value="defaultHandle"/>
</bean>
<bean id="viewResolver"
class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="viewClass">
<value>org.springframework.web.servlet.view.JstlView</value>
</property>
<property name="prefix">
<value>/</value>
</property>
<property name="suffix">
<value>.jsp</value>
</property>
</bean>
</beans>OK!到这里就算ok了 这是标准的struts+spring的配置文件。一定要加分哦!
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.0.xsd
你引入的约束是2.0的
就是包的问题 你要是用myeclipse内至的SPRING包肯定会出问题 我曾经出过 后来解决了 但是是糊涂着解决了 帮不上LZ忙 顶一个吧