struts 为什么用org.springframework.web.context.ContextLoaderListener才不会出错

Question

struts 为什么用org.springframework.web.context.ContextLoaderListener才不会出错，郁闷知道的能说下吗,谢谢

Answer 1

就是web.xml里要加入
<listener>

<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>

</listener>
而且要在lib下建立applicationContext.xml文件在这里struts和spring有什么关系

Answer 2

web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.4" xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee 
http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
<filter>
<filter-name>struts2</filter-name>
<filter-class>org.apache.struts2.dispatcher.FilterDispatcher</filter-class>
</filter> <filter-mapping>
<filter-name>struts2</filter-name>
<url-pattern>*.action</url-pattern>
</filter-mapping>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
</web-app>

Answer 3

struts.xml
<?xml version="1.0" encoding="UTF-8" ?>
<!DOCTYPE struts PUBLIC
    "-//Apache Software Foundation//DTD Struts Configuration 2.0//EN"
    "http://struts.apache.org/dtds/struts-2.0.dtd">
<struts>
<package name="ot" extends="struts-default">
<action name="hello" class="HelloAction">
<result name="success">/index.jsp</result>
</action>
</package></struts>

Answer 4

哈哈，这个我只得到：你的jar包里struts2-spring-plugin-2.0.11.1.jar
如果你不用spring  就把类似这个包去掉
如果你用spring就一定要加org.springframework.web.context.ContextLoaderListener 这个监听