例
<hibernate-mapping>
<class name="pojo.Unit" table="UNIT">
<id name="id" type="java.lang.Long">
<column name="ID" precision="22" scale="0" />
<generator class="sequence">
<param name="sequence">SEQ_UNIT </param>
</generator>
</id>
<property name="name" type="java.lang.String">
<column name="NAME" length="200" not-null="true" />
</property> <set name="users" cascade="none" lazy="true" inverse="true">
<key column="UNIT_ID" not-null="true"/>
<one-to-many class="pojo.User"/>
</set>
</class>
</hibernate-mapping>
我给出"pojo.Unit"和"users"两个字符串怎样得到Unit实体对应的users集合的元素类型,即pojo.User 或
public class Unit { private Long id; private String name; private Set <User> users = new LinkedHashSet <User>(); .........
public Set getUsers() {
return users;
} public void setUsers(Set users) {
this.users = users;
}
}
给定类名Unit.class和属性名users怎样获得users集合元素的类型
<hibernate-mapping>
<class name="pojo.Unit" table="UNIT">
<id name="id" type="java.lang.Long">
<column name="ID" precision="22" scale="0" />
<generator class="sequence">
<param name="sequence">SEQ_UNIT </param>
</generator>
</id>
<property name="name" type="java.lang.String">
<column name="NAME" length="200" not-null="true" />
</property> <set name="users" cascade="none" lazy="true" inverse="true">
<key column="UNIT_ID" not-null="true"/>
<one-to-many class="pojo.User"/>
</set>
</class>
</hibernate-mapping>
我给出"pojo.Unit"和"users"两个字符串怎样得到Unit实体对应的users集合的元素类型,即pojo.User 或
public class Unit { private Long id; private String name; private Set <User> users = new LinkedHashSet <User>(); .........
public Set getUsers() {
return users;
} public void setUsers(Set users) {
this.users = users;
}
}
给定类名Unit.class和属性名users怎样获得users集合元素的类型
解决方案 »
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