Jsp自定义标签访问struts2+spring+hibernate问题

Question

此回复为自动发出,仅用于显示而已，并无任何其他特殊作用
楼主【zhangsc】截止到2008-07-16 11:29:20的历史汇总数据(不包括此帖)：
发帖的总数量:41                       发帖的总分数:1840                     每贴平均分数:44                       
回帖的总数量:21                       得分贴总数量:1                        回帖的得分率:4%                       
结贴的总数量:37                       结贴的总分数:1760                     
无满意结贴数:4                        无满意结贴分:190                      
未结的帖子数:4                        未结的总分数:80                       
结贴的百分比:90.24 %               结分的百分比:95.65 %                  
无满意结贴率:10.81 %               无满意结分率:10.80 %                  
值得尊敬

Answer 1

可以从org.springframework.web.servlet.tags.RequestContextAwareTag继承，
getRequestContext().getWebApplicationContext()可以得到spring的context

Answer 2

要有一块全局的context,通过它来得，就不会有问题,
在启动的时候把它写进上下文

Answer 3

>>可以从org.springframework.web.servlet.tags.RequestContextAwareTag继承是指标签类可以这样写吗？
public class TestTag extends org.springframework.web.servlet.tags.RequestContextAwareTag{
       ......
       WebApplicationContextUtils.getRequiredWebApplicationContext().getBean("testDao");
   }
}
能说得详细些吗？谢谢！

Answer 4

给你个例子public class XxxTag extends RequestContextAwareTag {
  //覆盖doStartTagInternal方法
  protected int doStartTagInternal() throws Exception {
      this.getRequestContext().getWebApplicationContext().getBean("beanName");
      
  }
}

Answer 5

在标签中可以通过pageContext得到servletContext
ApplicationContext ctx = WebApplicationContextUtils.getWebApplicationContext(pageContext.getServletContext());
XxxService service = (XxxService)ctx.getBean("beanName");

Answer 6

用到什么jar包啊，我用了但报错，不知道什么原因org.apache.jasper.JasperException: javax.servlet.ServletException: java.lang.NoClassDefFoundError: org/springframework/web/bind/EscapedErrors
org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:522)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:398)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:342)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:267)
javax.servlet.http.HttpServlet.service(HttpServlet.java:717)
org.apache.struts.action.RequestProcessor.doForward(RequestProcessor.java:1069)
org.apache.struts.action.RequestProcessor.processForwardConfig(RequestProcessor.java:455)
org.apache.struts.action.RequestProcessor.process(RequestProcessor.java:279)
org.apache.struts.action.ActionServlet.process(ActionServlet.java:1482)
org.apache.struts.action.ActionServlet.doGet(ActionServlet.java:507)
javax.servlet.http.HttpServlet.service(HttpServlet.java:617)
javax.servlet.http.HttpServlet.service(HttpServlet.java:717)
org.apache.jsp.website.deptwebsite._0001.Index_jsp._jspService(Index_jsp.java:57)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70)
javax.servlet.http.HttpServlet.service(HttpServlet.java:717)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:374)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:342)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:267)
javax.servlet.http.HttpServlet.service(HttpServlet.java:717)
com.tiptech.platform.filters.SetEncodingFilter.doFilter(SetEncodingFilter.java:68)

Answer 7

我认为应该是这样的
在 WebApplicationContextUtils.getRequiredWebApplicationContext().getBean("testDao");
的getRequiredWebApplicationContext()的“()”中加入request.getSession().getServletContext()就可以了