问个hibernate映射的问题

Question

class Resume {
    private int id;
    private ResumeLangInfo enResumeInfo //对应resume_lang_info的一条数据 条件是ResumeLangInfoPK 的id与这个实体的id相等 并language = en;
    private ResumeLangInfo zhResumeInfo //对应resume_lang_info的一条数据 条件是ResumeLangInfoPK 的id与这个实体的id相等 并language = zh;
}private ResumeLangInfo {
    private ResumeLangInfoPK pk;
    //后面是语言相关的数据
}private ResumeLangInfoPK{
    private int resumeid;
    private String language;
}resume
   id int
   后面有很多String的字段 没什么关系resume_lang_info
   resumeid int 这个字段是参考 resume.id的
   language String "zh" "en"
这样是不是没有办法写这样的映射
一个类里有两个属性是指到同一个表的不同数据

Answer 1

给个思路
分别定义3个类对应以下3个配置文件：
<hibernate-mapping>
        <class name="org.tinna.resume" table="RESUME">
            <id name="resumeId" type="java.lang.Integer">
                <column name="resumeid" />
                <generator class="assigned" />
            </id>
            
            <one-to-one name="enResumeInfo" class="org.tinna.enResumeInfo" cascade="all"></one-to-one>
            <one-to-one name="zhResumeInfo" class="org.tinna.zhResumeInfo" cascade="all"></one-to-one>
        </class>
</hibernate-mapping>
<hibernate-mapping>
        <class name="org.tinna.enResumeInfo" table="RESUME">
            <id name="resumeId" type="java.lang.Integer">
                <column name="resumeid" />
                <generator class="assigned" />
            </id>
            <property name="enname" type="java.lang.String">
                <column name="enname" />
            </property>
            <property name="ensex" type="java.lang.String">
                <column name="ensex" />
            </property>
            <one-to-one name="resume" class="org.tinna.resume"></one-to-one>
        </class>
</hibernate-mapping><hibernate-mapping>
        <class name="org.tinna.zhResumeInfo" table="RESUME">
            <id name="resumeId" type="java.lang.Integer">
                <column name="resumeid" />
                <generator class="assigned" />
            </id>
            <property name="zhname" type="java.lang.String">
                <column name="zhname" />
            </property>
            <property name="zhsex" type="java.lang.String">
                <column name="zhsex" />
            </property>
            <one-to-one name="resume" class="org.tinna.resume"></one-to-one>
        </class>
</hibernate-mapping>