Struts 中的action 没有type属性，如何跳转？跳转到哪里去了？

Question

        public void process(HttpServletRequest request,
                        HttpServletResponse response)
        throws IOException, ServletException {        // Wrap multipart requests with a special wrapper
        request = processMultipart(request);        // Identify the path component we will use to select a mapping
        String path = processPath(request, response);
        if (path == null) {
            return;
        }
        
        if (log.isDebugEnabled()) {
            log.debug("Processing a '" + request.getMethod() +
                      "' for path '" + path + "'");
        }        // Select a Locale for the current user if requested
        processLocale(request, response);        // Set the content type and no-caching headers if requested
        processContent(request, response);
        processNoCache(request, response);        // General purpose preprocessing hook
        if (!processPreprocess(request, response)) {
            return;
        }
        
        this.processCachedMessages(request, response);        // Identify the mapping for this request
        ActionMapping mapping = processMapping(request, response, path);
        if (mapping == null) {
            return;
        }        // Check for any role required to perform this action
        if (!processRoles(request, response, mapping)) {
            return;
        }        // Process any ActionForm bean related to this request
        ActionForm form = processActionForm(request, response, mapping);
        processPopulate(request, response, form, mapping);
        
        // Validate any fields of the ActionForm bean, if applicable
        try {
            if (!processValidate(request, response, form, mapping)) {
                return;
            }
        } catch (InvalidCancelException e) {
            ActionForward forward = processException(request, response, e, form, mapping);
            processForwardConfig(request, response, forward);
            return;
        } catch (IOException e) {
            throw e;
        } catch (ServletException e) {
            throw e;
        }
            
        // Process a forward or include specified by this mapping
        if (!processForward(request, response, mapping)) {
            return;
        }
        
        if (!processInclude(request, response, mapping)) {
            return;
        }        // Create or acquire the Action instance to process this request
        Action action = processActionCreate(request, response, mapping);
        if (action == null) {
            return;
        }        // Call the Action instance itself
        ActionForward forward =
            processActionPerform(request, response,
                                 action, form, mapping);        // Process the returned ActionForward instance
        processForwardConfig(request, response, forward);    }直接返回了后面没有执行，应该没有执行action里的方法，也没有跳转

Answer 1

我想问，那要是没有执行action里的方法，没有跳转，按照<action input="/Logon.jsp" name="logonForm" path="/logonAction" scope="request" />，这个设置，从怎么完成登陆的啊？

Answer 2

楼主好好看看在JSP里面有没有相关的javascript,或许在JS里面通过:
window.document.forms['表单名'].action = action 的URL;
window.document.forms['表单名'].submit();方式来实现的action 跳转,可能是另外一个action来实现的