xml可以用Document doc = DocumentHelper.parseText(String xml), 然后用List list = doc.selectNodes(xpath)得到List,
/** * 按 name 进行比较. */ class BookNameComparator implements Comparator { public int compare(Object o1, Object o2) { Book book1 = (Book)o1; Book book2 = (Book)o2; return book1.name.compareTo(book2.name); } }
Object [] bookArray = bookList.toArray();
// 按照 name 排序. Arrays.sort(bookArray, new BookNameComparator()); dumpArray(bookArray);
System.out.println( "********** ");
// 按照 num 排序. Arrays.sort(bookArray, new BookNumComparator());
然后用List list = doc.selectNodes(xpath)得到List,
* 按 name 进行比较.
*/
class BookNameComparator implements Comparator {
public int compare(Object o1, Object o2) {
Book book1 = (Book)o1;
Book book2 = (Book)o2;
return book1.name.compareTo(book2.name);
}
}
// 按照 name 排序.
Arrays.sort(bookArray, new BookNameComparator());
dumpArray(bookArray);
System.out.println( "********** ");
// 按照 num 排序.
Arrays.sort(bookArray, new BookNumComparator());
<?xml version="1.0" encoding="GBK"?>
<devices>
<group name="缺省组">
<device>
<ip>172.19.254.1</ip>
<fname>f86afeab18c8e4c45b151637cfc30dfa.xml</fname>
</device>
<device>
<ip>172.19.90.115</ip>
<fname>cb9cce01dc992559a6ef1ac9b5b78ada.xml</fname>
</device>
</group>
<group name="测试组" />
</devices>
希望按照对group里的数据进行排序,基于ip递增排序,如何做?请给出完整代码。