请教正则表达式的写法

Question

(\d{4}\-\d{2}\-\d{2})\s(\d{2}:\d{2}:\d{2}) ¦\s(\d)\s(.+)\s(.+)--\s(.+\d)\s.+\s.+\->\d+\-\d+\=(\d+)

Answer 1

2008-08-19 10:40:36 ¦ 5 7_199258 -- 200->1219113635970-1219113636234=264 
(\d{4}\-\d{2}\-\d{2})\s(\d{2}:\d{2}:\d{2}) ¦\s(\d)\s(.+)\s--\s(\d+)->\d+-\d+=(\d+)2008-08-18 16:56:09 ¦ 5 X123 1_301 -- 第一次调用：5 X123 1_301->1219049769696-1219049769916=220 beans.service.out 
(\d{4}\-\d{2}\-\d{2})\s(\d{2}:\d{2}:\d{2}) ¦\s(\d)\s(.+)\s(.+)--\s(.+\d)\s.+\s.+\->\d+\-\d+\=(\d+)

Answer 2

非要用写正则嘛，用split更简单！！
String regex = "2008-08-19 10:40:36 | 5 7_199258 -- 200->1219113635970-1219113636234=264";
String arr[] = regex.split(" |->|=");
for(int i=0;i<arr.length;i++){
System.out.println(arr[i]);
}如果格式固定的话，那么可以直接取出
arr[0] = 2008-08-19
arr[1] = 10:40:36
arr[3] = 5
arr[4] = 7_199258
arr[6] = 200
arr[8] = 264