求一条SQL语句 select * from user u1 where u1.name in (select u2.name from user u2 group by u2.name having count(u2.name)>1)期待谁给个简单的…… 解决方案 » 免费领取超大流量手机卡,每月29元包185G流量+100分钟通话, 中国电信官方发货 select top 4 * from [user] where [name] in (select [name] from [user] group by [name] having count([name])>1)经过测试。 select top 4 * from [user] where [name] in ( select [name] from [user] group by [name] having count([name])>1 ) mysqlselect name form user u1 where u1.name in (select u2.name from user u2)limit 1,64; 请教一个hql 转换类型的问题 Spring Portal MVC 紧急,求助 为什么我的视图解析器不起作用?InternalResourceViewResolver 关于tiles的问题.. webwork2中的Resource Bundle怎么配置? 200分,求取java操纵xml文件的读写,并根据xml生成树型菜单的代码示例 求Eclipse+easy struts开发步骤 诚聘JAVA开发人员(专职) DOM分析的问题,请教各位师兄? 急等给分!!!! 求,正则表达式验证,比例的 喜欢交流的人进来看看
select top 4 * from [user] where
[name] in
(select [name] from [user]
group by [name] having count([name])>1
)经过测试。
[name] in
( select [name] from [user]
group by [name] having count([name])>1
)
select name form user u1 where u1.name in
(select u2.name from user u2)
limit 1,64;